Question

我必须编写一个JPA查询来选择MySQL数据库中的数据。

我有这部分代码：

SELECT NEW com.fiat.sc.um.mdm.bean.Vendor
(e.fgpVndrNumber, e.companyName1, e.vndrCountry, 
e.city, e.postalCode, e.street, e.vatRegistrNum, 
e.vendorTypeDesc, e.companyName2, e.taxNumber2, 
e.taxNumber1, e.organizationCode) 
FROM ScVendor e

我想在where子句中添加：

WHERE str(e.fgpVndrNumber) LIKE '%123%'

或

to_char(e.fgpVndrNumber) LIKE '%123%'

简而言之，我必须在String中转换一个Integer。

但我得到了一个错误。

建议？

修改

这是完整的Java代码：

String selAndForm = "SELECT NEW com.fiat.sc.um.mdm.bean.Vendor(e.fgpVndrNumber, e.companyName1, e.vndrCountry,"
                + " e.city, e.postalCode, e.street, e.vatRegistrNum, e.vendorTypeDesc, e.companyName2, e.taxNumber2, "
                + "e.taxNumber1, e.organizationCode)  FROM ScVendor e ";

        String where = null;

        if (isNotNull(companyName)) {
            if (searchCriteriaCompName != null) {
                if (searchCriteriaCompName.equals("contains")) {
                    companyName = "%" + companyName + "%";
                }
                if (searchCriteriaCompName.equals("startWith")) {
                    companyName = companyName + "%";
                }
                if (searchCriteriaCompName.equals("endWith")) {
                    companyName = "%" + companyName;
                }
            }

            if (where == null) {
                where = "WHERE lower(e.companyName1) like '" + companyName.toLowerCase() + "'";
            } else {
                where = where + " AND lower(e.companyName1) like '" + companyName.toLowerCase() + "'";
            }
        }

        if (isNotNull(immediateParent)) {
            if (searchCriteriaParentCode != null) {
                if (searchCriteriaParentCode.equals("contains")) {
                    immediateParent = "%" + immediateParent + "%";
                }
                if (searchCriteriaParentCode.equals("startWith")) {
                    immediateParent = immediateParent + "%";
                }
                if (searchCriteriaParentCode.equals("endWith")) {
                    immediateParent = "%" + immediateParent;
                }
                if (searchCriteriaParentCode.equals("equals")) {
                    // do nothing
                }
            }

            if (where == null) {
                where = "WHERE e.immediateParent LIKE '" + immediateParent + "'";
            } else {
                where = where + " AND e.immediateParent LIKE '" + immediateParent + "'";
            }
        }


        if (isNotNull(supplierCode)) {

            logger.debugT("supplierCode=" + supplierCode);

            if (searchCriteriaParentCode != null) {
                if (searchCriteriaSuppCode.equals("contains")) {
                    supplierCode = "%" + supplierCode + "%";
                }
                if (searchCriteriaSuppCode.equals("startWith")) {
                    supplierCode = supplierCode + "%";
                }
                if (searchCriteriaSuppCode.equals("endWith")) {
                    supplierCode = "%" + supplierCode;
                }
                if (searchCriteriaSuppCode.equals("equals")) {
                    // do nothing
                }
            }

            if (where == null) {
                where = "WHERE e.fgpVndrNumber.toString() like '" + supplierCode + "'";
            } else {
                where = where + " AND e.fgpVndrNumber.toString() like '" + supplierCode + "'";
            }
        }


        StringBuffer SQL = new StringBuffer();

        SQL.append(selAndForm);
        SQL.append(where);
        SQL.append(" AND e.deletedAt IS NULL");

        logger.debugT(SQL.toString());
        Query query = eManager.createQuery(SQL.toString());

fgpVendorNumber是一个整数。我想用String转换它。

Answer 1

搜索部分号码无需显式投射。

以下查询格式应该没有语法或逻辑错误。

select ...
  from ...
 where e.fgpVndrNumber like '%123%'

Answer 2

在MySql数据库中使用强制转换功能。

WHERE cast(e.fgpVndrNumber as varchar) LIKE '%123%'

另见

MySql Cast

Answer 3

在JPA JPQL中尝试将整数与字符串进行比较会导致错误。
我能够将Integer转换成可以进行比较的String：

WHERE substring(xInteger, 0) like '%stringFilter%'

Answer 4

我可以在我的JPA查询中使用TRIM：

WHERE TRIM(e.fgpVndrNumber as varchar) LIKE '%123%'

JPA整数转换为String查询的字符串

4 个答案: