Question

我在codeigniter中遇到问题。我尝试了不同的东西，但我找不到解决方案。

这是表格：

<form method="post" action="<?php echo base_url(); ?>cms/cms/newUser">
<div class="row">
    <div class="col-md-3">
        Naam:
    </div>
    <div class="col-md-9">
        <input type="text" id="naam" name="username" />
    </div>
</div>

<div class="row">
    <div class="col-md-3">
        E-mail:
    </div>
    <div class="col-md-9">
        <input type="email" name="mail" id="email" />
    </div>
</div>

<div class="row">
    <div class="col-md-3">
        Passwoord:
    </div>
    <div class="col-md-9">
        <input type="password" name="pass" id="password" />
    </div>
</div>

<div class="row">
    <div class="col-md-8 col-md-offset-2">
        <input type="submit" name="aanmaken" class="btn btn-block btn-info" value="aanmaken" />
    </div>
</div>

在我的控制器中我处理来自表单的数据。控制器位于controllers / cms / cms.php

class Cms extends MY_Controller 
{
    public function newUser()
    {
        if(isset($_POST))
        {
            echo "verwerk deze data <br>";

            if(isset($_POST['username']))
            {
                echo 'naam is set!';
            }
            else {
                echo 'naam is not set!';
            }

            $naam = $_POST['username'];
            $mail = $_POST['email'];
            $pass = $_POST['password'];

            echo "naam: " . $naam . "<br>";
            echo "mail: " . $mail . "<br>";
            echo "pass: " . $pass . "<br>";

            $time = new DateTime();
            $time->setTimezone(new DateTimeZone ('Europe/Brussels'));
            $tijd = $time->format('Y-m-d H:i:s');

            include_once('application/libraries/PasswordHash.php');

            $hasher = new PasswordHash(12,false);
            $passwoord = $hasher->HashPassword($pass);

            $gebruiker = new Gebruiker();
            $gebruiker->naam = $naam;
            $gebruiker->email = $mail;
            $gebruiker->paswoord = $passwoord;
            $gebruiker->laatsteLogin = $tijd;
            $gebruiker->active = 0;

            echo "coded pas" . $passwoord . "<br>";
        }
        else 
        {
            echo "no post";
        }
    }

当我检查我的网站并填写表格时，我得到3个php错误，我从帖子中放入变量的值不存在。 if（isset）函数也表示该变量未设置。我不知道为什么表单行动不起作用。

我甚至尝试过codeigniter方式，但它给出了相同的结果。

$name = $this->input->post('username');

感谢您的帮助。

Answer 1

您只需要传递controllername / func_name并将控制器文件保存在controller目录中然后尝试CI方式

<?php echo form_open("cms/newUser");?>
<?php echo form_close();?>

或

<form method="post" action="<?php echo base_url(); ?>cms/newUser">

否则你需要使用routing来告诉我在该路线上选择这个控制器为此，请转到config / routes.php并添加如下路线： -

$route['cms'] = "cms/cms";

Answer 2

在表单标记

中

<form method="post" action="<?php echo base_url(); ?>cms/cms/newUser">

cms是控制器的名称，您已经使用过两次。试试

<form method="post" action="<?php echo base_url(); ?>cms/newUser">

Answer 3

HTML:

enter code here

<form method="post" action="<?php echo site_url(); ?>/cms/cms/newUser">
<div class="row">
<div class="col-md-3">
    Naam:
</div>
<div class="col-md-9">
    <input type="text" id="naam" name="username" />
</div>

电子邮件：

<div class="row">
<div class="col-md-3">
    Passwoord:
</div>
<div class="col-md-9">
    <input type="password" name="pass" id="password" />
</div>
</div>

<div class="row">
<div class="col-md-8 col-md-offset-2">
    <input type="submit" name="aanmaken" class="btn btn-block btn-info" value="aanmaken" />
</div>
</div>

PHP:
class Cms extends MY_Controller 
{
public function newUser()
{
    if(isset($_POST))
    {
        echo "verwerk deze data <br>";

        if($this->input->post('username'))
        {
            echo 'naam is set!';
        }
        else {
            echo 'naam is not set!';
        }

        $naam = $this->input->post('username');
        $mail = $this->input->post('mail');
        $pass = $this->input->post('pass');

        echo "naam: " . $naam . "<br>";
        echo "mail: " . $mail . "<br>";
        echo "pass: " . $pass . "<br>";

        $time = new DateTime();
        $time->setTimezone(new DateTimeZone ('Europe/Brussels'));
        $tijd = $time->format('Y-m-d H:i:s');

        include_once('application/libraries/PasswordHash.php');

        $hasher = new PasswordHash(12,false);
        $passwoord = $hasher->HashPassword($pass);

        $gebruiker = new Gebruiker();
        $gebruiker->naam = $naam;
        $gebruiker->email = $mail;
        $gebruiker->paswoord = $passwoord;
        $gebruiker->laatsteLogin = $tijd;
        $gebruiker->active = 0;

        echo "coded pas" . $passwoord . "<br>";
    }
    else 
    {
        echo "no post";
    }
}

$ this-＆gt; input-＆gt; post（＆＃39;＆＃39;）将自动检查不需要isset（）。 $ this-＆gt; input-＆gt; post（＆＃39;＆＃39;）将取名而不是id

Answer 4

尝试加载表单助手并使用此代码

控制器：

$ this-＆gt; viewContent [＆＃39; form_action＆＃39;] = base_url（）。＆＃34; cms / cms / newUser＆＃34 ;; $这 - ＆GT;负载＆gt;查看（＆＃39; your_view_page＆＃39;，$这 - ＆GT; viewContent）;

视图： echo form_open（$ form_action）;

表单操作codeigniter找不到发布数据

4 个答案: