我有一个按钮,当单击时,使用JQuery .after()将表单输入字段和按钮(删除)插入到表单中。这很好用。
插入的按钮具有单击时应运行的功能.click - 它不起作用。
<script type="text/javascript">
$("#addAQuestion").click(function(){
var begin = "<tr>";
var question = "<td><input type='text' name='question'/>";
var deleteButton = "<input type='button' class='deleteQuestion' name='delete' value='Del' /></td>";
var end = "</tr>";
$("#questions").after(begin + question + deleteButton + end);
});
$(".deleteQuestion").click(function(){
alert('test');
//$(this).parent().empty();
});
</script>
当用户点击.deleteQuestion按钮时,如何触发警报?
谢谢!
答案 0 :(得分:2)
因为在进行事件连线时,删除按钮不存在。
考虑查看jquery的.live()api来解决这个问题,或者将删除按钮的连接点击到另一个点击处理程序内部(所以它在添加按钮后连接)
另外,你应该考虑使用dom操作apis而不是字符串连接。
答案 1 :(得分:2)
在添加事件时,您没有将事件分配给dom对象,请按如下所示更改代码:
<script type="text/javascript">
$("#addAQuestion").click(function(){
var begin = "<tr>";
var question = "<td><input type='text' name='question'/>";
var deleteButton = "<input type='button' class='deleteQuestion' name='delete' value='Del' /></td>";
var end = "</tr>";
$("#questions").after(begin + question + deleteButton + end);
$(".deleteQuestion").click(function(){
alert('test');
//$(this).parent().empty();
});
});
</script>
答案 2 :(得分:2)
这应该有效:
<script type="text/javascript">
$("#addAQuestion").click(function(){
var begin = "<tr>";
var question = "<td><input type='text' name='question'/>";
var deleteButton = "<input type='button' class='deleteQuestion' name='delete' value='Del' /></td>";
var end = "</tr>";
$("#questions").after(begin + question + deleteButton + end);
$(".deleteQuestion").click(function(){
alert('test');
//$(this).parent().empty();
});
});
</script>
答案 3 :(得分:2)
执行顺序。将节点添加到DOM的代码是异步的 - 它在点击时发生。因此,基本上,在这些元素位于DOM之前,您将点击事件附加到.deleteQuestion
个节点。
有两种方法可以解决这个问题。
1)修复执行顺序,以便正确附加点击事件
<script type="text/javascript">
$("#addAQuestion").click(function(){
var begin = "<tr>";
var question = "<td><input type='text' name='question'/>";
var deleteButton = "<input type='button' class='deleteQuestion' name='delete' value='Del' /></td>";
var end = "</tr>";
$("#questions").after(begin + question + deleteButton + end);
// Has to be here, right after they're added to the DOM
$(".deleteQuestion").click(function(){
alert('test');
//$(this).parent().empty();
});
});
</script>
2)或者,你可以使用jQuery的live()函数通过事件委托来处理这个问题
<script type="text/javascript">
$("#addAQuestion").click(function(){
var begin = "<tr>";
var question = "<td><input type='text' name='question'/>";
var deleteButton = "<input type='button' class='deleteQuestion' name='delete' value='Del' /></td>";
var end = "</tr>";
$("#questions").after(begin + question + deleteButton + end);
});
$(".deleteQuestion").live( 'click', function(){
alert('test');
//$(this).parent().empty();
});
</script>