Question

我正在设计连接到oracle DB的三重下拉列表。当用户选择3个值时，它必须将值更新为db。但我有问题，第三个下拉列表没有显示在print_r，这意味着我不能把第三个值放在数据库中

这是该计划的JS，

function getThickness(projectName) {        

    var strURL="findThickness.php?project="+projectName;
    var req = getXMLHTTP();

    if (req) {

        req.onreadystatechange = function() {
            if (req.readyState == 4) {
                // only if "OK"
                if (req.status == 200) {                        
                    document.getElementById("thicknessDiv").innerHTML=req.responseText;
                    document.getElementById("baseplateDiv").innerHTML='<select name="baseplate">'+
                    '<option>Select Baseplate</option>'+'</select>';                        
                } else {
                    alert("Problem while using XMLHTTP:\n" + req.statusText);
                }
            }               
        }           
        req.open("GET", strURL, true);
        req.send(null);
    }       
}

function getBaseplate(projectName,thicknessVal) {       
    var strURL="findBaseplate.php?project="+projectName+"&thicknessValue="+thicknessVal;
    var req = getXMLHTTP();

    if (req) {
        req.onreadystatechange = function() {
            if (req.readyState == 4) {
                // only if "OK"
                if (req.status == 200) {                        
                    document.getElementById("baseplateDiv").innerHTML=req.responseText;                     
                } else {
                    alert("Problem while using XMLHTTP:\n" + req.statusText);
                }
            }               
        }           
        req.open("GET", strURL, true);
        req.send(null);
    }

}

和findThickness.php，

<?php 
$projectName = strval($_GET['project']); 

$query = "SELECT DISTINCT THICKNESS FROM COMPONENT_CUTTING WHERE PROJECT_NAME = :projectName";
$result = oci_parse($conn, $query);

oci_bind_by_name($result, ":projectName", $projectName);

oci_execute($result);

?>

<select name="thickness" onChange="getBaseplate('<?php echo $projectName?>',(this.value));">

<option>Select Thickness</option>
    <?php while ($row = oci_fetch_array($result, OCI_BOTH)) { ?>
<option value=<?php echo $row['THICKNESS']?>><?php echo $row['THICKNESS']?></option>
    <?php } ?>

</select>

和findBasePlate.php就像这样

<?php 
$projectName    = strval($_GET['project']); 
$thicknessValue = intval($_GET['thicknessValue']);

$query = "SELECT BASE_PLATE FROM COMPONENT_CUTTING WHERE THICKNESS = :thicknessVal AND PROJECT_NAME = :projectName";
$result = oci_parse($conn, $query);

oci_bind_by_name($result, ":projectName", $projectName);
oci_bind_by_name($result, ":thicknessVal", $thicknessValue);

oci_execute($result);
?>


<select name="baseplate">

<option>Select Baseplate</option>
<?php 
    while($row = oci_fetch_array($result, OCI_BOTH)) { ?>
        <option value><?php echo $row['BASE_PLATE']?></option>
<?php } ?>
</select>

并在用户点击提交时调用的save.php中显示一个print_r，该值显示该值，并且显示如下所示，

Array ( [projectName] => ECOFATTYACHID [thickness] => 28 [baseplate] => [quantityToCut] => 4 [text_remarks] => [submit] => Submit Request )

我不知道我的代码有什么问题。所以请告诉我这个，我非常感谢你们帮助

Answer 1

请将其放在引号<option value=<?php echo $row['THICKNESS']?>>中例如<option value="<?php echo $row['THICKNESS']?>">
它将被解释为<option value=option_xxx>，并且可能无法给出预期的结果。

您还需要将<option value><?php echo $row['BASE_PLATE']?></option>更改为<option><?php echo $row['BASE_PLATE']?></option>删除value

第三个下拉值未显示在print_r中

1 个答案: