Question

我怎样才能创建一个循环来创建一个空格，这样我就可以输出更多的空格而不是更少的空格。输入的字符串应该以星号为中心。我无法弄清楚如何让for循环来做到这一点。所以，如果你能帮我找出原因或修复我的代码那么棒。

/*

*******
*     *
*  I  *
*     *
******* 
instead of 
***
* *
*I*
* *

* /

    public static void main(String[] args) {
    // TODO code application logic here
    Scanner keyboard = new Scanner (System.in);
    System.out.print("Enter a string: ");
      String word = keyboard.nextLine();
    int len=word.length();
    for(int i=0;i<len+2;i++)
    {
        System.out.print("*");
    }       
    System.out.println();
    System.out.print("*");
    for(int i=0;i<len;i++) //adjust the number of tabs
    {
        System.out.print(" ");
    }
    System.out.print("*");
    System.out.println();
    System.out.println("*"+word+"*");
    System.out.print("*");
    for(int i=0;i<len;i++) // adjust the number of tabs
    {
        System.out.print(" ");
    }
    System.out.print("*");
    System.out.println();

    for(int i=0;i<len+2;i++)
    {
        System.out.print("*");
    }
}

Answer 1

我不确定您是只想要水平间距还是水平和垂直间距

如果你只想要水平间距，那么你可以使用下面的

计算字符串的长度（如果是多行，则计算任何行的最大长度）-maxlen
决定你想要多少间距（让我们称之为x）
输出长度为2 + maxlen +（2 * x）
输出2个星号，间隔为maxlen +（2 * x）
输出星号，空格，字符串，sapce，星号
重复步骤4
重复步骤3

你可以扩展它以获得垂直间距

Answer 2

import java.util.Scanner;
import static java.lang.System.out;

public class SomeClass
{

    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);

        out.print("Enter a string: ");

        String word = input.nextLine();

        input.close();

        out.print("\n\n");

        // First find out how many wide the first border should be

        int top = word.length() + 4/*spaces */ + 2/*asterisks */ ;

        // Print out that many asterisks
        while(top != 0) out.printf("*", top--);

        // Print out the second line, which is the length of top, except only 
        //   the first and last character are asterisks.
        out.printf("\n*  %" + word.length() + "s  *\n", " ");

        // Print out the word
        out.printf("*  %s  *", word);

        out.printf("\n*  %" + word.length() + "s  *\n", " ");

        int bot = word.length() + 6;

        while(bot != 0) out.printf("*", bot--);
    }

}

控制台输出：

    Enter a string: STACK OVERFLOOOWWWW


    *************************
    *                       *
    *  STACK OVERFLOOOWWWW  *
    *                       *
    *************************

Answer 3

我设法使用静态方法和一些循环来解决问题。希望它可以帮助您满足您的需求。无论字符串长度如何，它都应该看起来正确。

public class SO5 {
public static void main(String[] args) {
String st = "Photograph"; //String
    int length = st.length() + 4; //Length of string plus 4, for star and space at front and back 

    for(int i = 0; i < 9; i++){//Number of levels needed
        if(i == 0 || i == 8){//Start or end
            printForLength("*", length); //Print relevant number of start
            System.out.println(); //Next line
        } else if(i % 2 == 0){ //If an even number
            if(i == 4){ //If the middle
                System.out.println("* " + st + " *"); //Print star our string plus star
            } else { //If not middle
                System.out.print("*"); //Star
                printForLength(" ", length - 2); //spaces for length of string -2 for start and end stars
                System.out.print("*");//End star
                System.out.println();//New line
            }
        }
    }
}


//Method prints a character for a set number of times
public static void printForLength(String s, int length){ 
    for(int j = 0; j < length; j++){
        System.out.print(s);
    }
}

}

祝你好运！

如何使循环以字符串为中心？

3 个答案: