Question

Lisa再次......如前所述，我正在建立一个系统，我想从数据库中加载内容，在我的AdminCP中我希望用户能够编辑内容，所以这就是我和＃39;在changecontent.php中做：

if(isset($_POST['change_content'])) {
  $name = $_POST['content'];
  $errorscontent = $users->changeContent($text);
}

另一个文件：

    public function changeContent($text) {
    $errorscontent = array();
    $stmt = $this->mysqli->prepare("UPDATE cms_content WHERE title='homepage' SET text = ? ");
    $stmt->bind_param('s', $text);
    $stmt->execute();
    $stmt->close();
    $errorsslide[] = "<div class='alert alert-success'><button type='button' class='close' data-dismiss='alert'>x</button><strong>Success!</strong> Homepage content Changed successfully!</div>";
    return $errorscontent;
}

有谁知道我做错了什么？

莉莎

Answer 1

SET必须在您的查询中WHERE之前：

$stmt = $this->mysqli->prepare("UPDATE cms_content WHERE title='homepage' SET text = ? ");

应该是：

$stmt = $this->mysqli->prepare("UPDATE cms_content SET text = ? WHERE title='homepage' ");

＆＃34; UPDATE cms_content WHERE title =＆＃39;主页＆＃34; SET值=？＆＃34;

1 个答案: