<div class="inner_body_left">
<li>
Lake 2014: 9th Biennial Lake Symposium on "
<a target="_blank" href="/events/CES_TVR_LAKE_2014_brochure_2FEb2014.pdf">Conservation of Wetland Ecosystems in Western Ghats</a>
", 13-15th November 2014
</li>
</div>
在这里,我想获得西湖高尔夫球场第9届双年湖湿地生态系统保护研讨会&#34;。有没有办法用单一的Xpath表达式获得li标签和标签的内容?提前谢谢。
答案 0 :(得分:0)
您可以使用以下 XPATH ,使用string-join
:
string-join(//li/text(),"")
<强>输出强>
Lake 2014: 9th Biennial Lake Symposium on "", 13-15th November 2014
或者,使用translate
来满足您的需求: -
translate(string-join(//li/text(),""),'",','')
<强>输出强>
Lake 2014: 9th Biennial Lake Symposium on 13-15th November 2014