我在这里:
public function index()
{
$this->is_logged_in();
$this->load->model('ReportModel');
$this->load->model('ConsultantModel');
if (isset($_POST['report'])){
$reports=$this->ReportModel->search($_POST['report']);
} else {
$reports=$this->ReportModel->get_last_ten_entries();
}
$models=$this->ReportModel->getModel();
$terms=$this->ReportModel->getTerm();
$username = $this->session->userdata('username');
$data['query'] = $this->ConsultantModel->getConsultantData($username);
//i want to send data to the report list view
//$this->load->view('report/reportlist', $data);
$this->load->view('report/reportlist', array('reports'=>$reports,'terms'=>$terms,'models'=>$models));
}
我想在一个视图(报告/报告列表)中传递数组和数据。我知道这是可能的,因为它是一个非常简单的想法,但我不知道如何。即使它不能,我知道你们知道一些技巧。如果你知道的话,请回答这个问题。
答案 0 :(得分:0)
public function index()
{
$this->is_logged_in();
$this->load->model('ReportModel');
$this->load->model('ConsultantModel');
$data = array();
if (isset($_POST['report'])){
$data['reports'] = $this->ReportModel->search($_POST['report']);
} else {
$data['reports'] = $this->ReportModel->get_last_ten_entries();
}
$data['models'] = $this->ReportModel->getModel();
$data['terms'] = $this->ReportModel->getTerm();
$username = $this->session->userdata('username');
$data['query'] = $this->ConsultantModel->getConsultantData($username);
$this->load->view('report/reportlist', $data);
}
您可以在观看中使用以下内容 -
1)报告 -
i)如果是单值 -
echo $reports;
ii)如果是阵列
foreach($reports as $report)
{
echo $report[..];
}
同样的休息。