Question

我在这里遵循这个教程并尝试完全按照那里解释的那样做。我虽然收到了错误：

警告：mysqli_error（）预计在第12行的/storage/content/37/191037/website.se/public_html/newsite/admin/perfis/index.php中只提供1个参数0

以下是代码：

<?php

session_start();
require_once "scripts/conector.php";
// Determine which page ID to use in our query below -----------------------------------------------------------------------------------
if (!$_GET['pid']) {
    $pageid = '1';
} else {
    $pageid = ereg_replace("[^0-9]", "", $_GET['pid']); // filter everything but numbers for security
}
// Query the body section for the proper page
$sqlCommand = "SELECT pagebody FROM pages WHERE id='$pageid' LIMIT 1"; 
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 
while ($row = mysqli_fetch_array($query)) { 
    $body = $row["pagebody"];
} 
mysqli_free_result($query); 
//---------------------------------------------------------------------------------------------------------------------------------------------------------------
// Query the module data for display ---------------------------------------------------------------------------------------------------------------
$sqlCommand = "SELECT modulebody FROM modules WHERE showing='1' AND name='footer' LIMIT 1"; 
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 
while ($row = mysqli_fetch_array($query)) { 
    $footer = $row["modulebody"];
} 
mysqli_free_result($query); 
//---------------------------------------------------------------------------------------------------------------------------------------------------------------
// Query the module data for display ---------------------------------------------------------------------------------------------------------------
$sqlCommand = "SELECT modulebody FROM modules WHERE showing='1' AND name='custom1' LIMIT 1"; 
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 
while ($row = mysqli_fetch_array($query)) { 
    $custom1 = $row["modulebody"];
} 
mysqli_free_result($query); 
//---------------------------------------------------------------------------------------------------------------------------------------------------------------
// Build Main Navigation menu and gather page data here -----------------------------------------------------------------------------
$sqlCommand = "SELECT id, linklabel FROM pages WHERE showing='1' ORDER BY id ASC"; 
$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); 

$menuDisplay = '';
while ($row = mysqli_fetch_array($query)) { 
    $pid = $row["id"];
    $linklabel = $row["linklabel"];

    $menuDisplay .= '<a href="index.php?pid=' . $pid . '">' . $linklabel . '</a><br />';

} 
mysqli_free_result($query); 
//---------------------------------------------------------------------------------------------------------------------------------------------------------------
//mysqli_close($myConnection); 
?>

<?php echo $menuDisplay; ?>

我不明白我做错了什么。数据库运行良好，我已手动插入数据并且它工作正常，我也使用相同的数据库来建立登录机制，它也正常工作。

有人能发现错误吗？

Answer 1

更改

die (mysqli_error());

到

die('Error: ' . mysqli_error($myConnection));

查询中的

$query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error());

Answer 2

尝试

mysqli_error($myConnection)

因为mysqli_error（）需要链接标识符作为参数

有关详细信息，请参阅http://de3.php.net/mysqli_error

警告：mysqli_error（）正好需要1个参数，给出0

2 个答案: