Question

我需要在echo $_GET['id'];中使用oci_parse，但似乎无法使其正常运行。我试过在＆＃39;，＆＃34;等但都没有奏效。

代码：

  $stid = oci_parse($conn, "

    SELECT COLA, 
      (SELECT COLB FROM T2 WHERE T2.COLB = echo $_GET['id'];)
    FROM T1
    WHERE T1.COLA = echo $_GET['id'];

  ");

Answer 1

方法1

$stid = oci_parse($conn, "SELECT COLA, 
    (SELECT COLB FROM T2 WHERE T2.COLB = {$_GET['id']})
  FROM T1
    WHERE T1.COLA = {$_GET['id']}");

方法 - 2

    $stid = oci_parse($conn, "SELECT COLA, 
    (SELECT COLB FROM T2 WHERE T2.COLB = ".$_GET['id'].")
  FROM T1
    WHERE T1.COLA = ".$_GET['id']."");

Answer 2

在查询中使用它之前，你必须做一些验证。

if (ctype_digit($_GET['id'])){
    $dIdUser = $_GET['id'];

    $stid = oci_parse($conn, "
    SELECT COLA, 
      (SELECT COLB FROM T2 WHERE T2.COLB =$dIdUser ;)
    FROM T1
    WHERE T1.COLA = $dIdUser;

  ");

}

Answer 3

也许你需要在查询后首先执行查询？

<?php

$conn = oci_connect('hr', 'welcome', 'localhost/XE');

// Parse the statement. Note there is no final semi-colon in the SQL statement
$stid = oci_parse($conn, 'SELECT * FROM employees');
oci_execute($stid);

echo "<table border='1'>\n";
while ($row = oci_fetch_array($stid, OCI_ASSOC+OCI_RETURN_NULLS)) {
    echo "<tr>\n";
    foreach ($row as $item) {
        echo "    <td>" . ($item !== null ? htmlentities($item, ENT_QUOTES) : "&nbsp;") . "</td>\n";
    }
    echo "</tr>\n";
}
echo "</table>\n";

?>

在oci_parse中使用PHP $ _GET

3 个答案: