Question

我有一个insert命令，其值根据另一个表上的货币值计算。 Sql代码类似于

INSERT INTO table1 (column1,column2,column3,column4,column5,column6)
VALUES
(
value1 * (SELECT currency FROM currency_table WHERE date=date1),
value2 * (SELECT currency FROM currency_table WHERE date=date1),
value3 * (SELECT currency FROM currency_table WHERE date=date1),
value4 * (SELECT currency FROM currency_table WHERE date=date2),
value5 * (SELECT currency FROM currency_table WHERE date=date2),
value6 * (SELECT currency FROM currency_table WHERE date=date2),
)

UPDATE table1 
SET column1 = value7 * (SELECT currency FROM currency_table WHERE date=date1),
column2 = value8 * (SELECT currency FROM currency_table WHERE date=date1),
column3 = value9 * (SELECT currency FROM currency_table WHERE date=date1),
column4 = value10 * (SELECT currency FROM currency_table WHERE date=date2),
column5 = value11 * (SELECT currency FROM currency_table WHERE date=date2),
column6 = value12 * (SELECT currency FROM currency_table WHERE date=date2)
WHERE column7 = value13

所以我得到货币价值3倍。考虑这是一个例子，因为我的实际查询有10次调用。

如何更改此查询以获取货币值不是3次，而只是1次。

考虑currency_table只有1行。

忘了提到这个查询是针对sql server 2008的

Answer 1

尝试使用INSERT：

INSERT INTO table1 (column1,column2,column3)
VALUES
SELECT value1*currency, value2*currency, value3*currency
FROM currency_table;

Answer 2

插入是Guneli提供的内容。从语法上讲，查询不正确。使用

INSERT INTO table1 (column1,column2,column3,column4,column5,column6)
SELECT value1*currency1, value2*currency1, value3*currency1,
       value4*currency2, value5*currency2, value6*currency2
FROM (select (select currency from currency_table where date = @date1) currency1,
(select currency from currency_table where date = @date2) currency2) A;

要进行更新，您可以使用以下命令。

UPDATE t1 
SET t1.column1 = value1 * c.currency1,
t1.column2 = value2 * c.currency1,
t1.column3 = value3 * c.currency1,
t1.Column4 = value4 * c.currency2,
t1.column5 = value5 * c.currency2,
t1.column6 = value6 * c.currency2
from table1 t1, 
(select (select currency from currency_table where date = @date1) currency1, 
   (select currency from currency_table where date = @date2) currency2) C
WHERE t1.column4 = value4

它将与currency_table进行交叉连接，并假设currency_table具有单行，它将正确更新。

Answer 3

加入怎么样？我不确定条件是你在没有任何where子句的情况下选择货币。

UPDATE table1 t1 INNER JOIN currency_table c ON [condition??]
SET t1.column1 = value1 * c.currency,
t1.column2 = value2 * c.currency,
t1.column3 = value3 * c.currency,
WHERE t1.column4 = value4

在插入查询中使用Select语句中的相同值

3 个答案: