Question

#include <stdio.h>
#include <string.h>
#include <stdlib.h>


 void encrypting(char cipher[25], int shift, int num)
{ int i;
 for ( i=0; i < num; i++)
{
    if (cipher[i] >= 'A' && cipher[i] <= 'Z')
    {
        cipher[i] = (char)(((cipher[i] + shift - 'A' + 26) % 26) + 'A');
    }
    else if (cipher[i] >= 'a' && cipher[i] <= 'z')
    {
        cipher[i] = (char)(((cipher[i] + shift - 'a' + 26) % 26) + 'a');
    }
}
}

 void decrypting(char cipher[25], int shift, int num)
{ inti;
 for ( i=0; i < num; i++)
{
    if (cipher[i] >= 'A' && cipher[i] <= 'Z')
    {
        cipher[i] = (char)(((cipher[i] - shift - 'A' + 26) % 26) + 'A');
    }
    else if (cipher[i] >= 'a' && cipher[i] <= 'z')
    {
        cipher[i] = (char)(((cipher[i] - shift - 'a' + 26) % 26) + 'a');
    }
    }
}

int main ()
{
char text[10];
static const char encrypt[] = "2";
static const char decrypt[] = "1";
int shift;
char cipher[25];
int result1;
int result2;
int num;
int i;



printf( "Enter operation: encrypt or decrypt/n" );
printf( "Press 1 to Encrypt or 2 to Decrypt" );
scanf("%c",&text) ;
printf( "Enter shift key" );
scanf("%d",&shift) ;
printf("Enter text to encrypt/decrypt") ;
fflush(stdin);
scanf( "%c",&cipher) ;

num = strlen (cipher);

result1 = strcmp (text, encrypt);
result2 = strcmp (text, decrypt);

if(result1 == 0)
{
    decrypting(cipher, shift, num);
}
else{exit(0);}

if(result2 == 0)
{
    encrypting(cipher, shift, num);
}
else{exit(0);}

printf("Result");
printf("%d",cipher);
}

这是我的代码，用于根据用户选择对字符串进行加密或解密的简单程序。

当我尝试编译时，代码产生了这个错误，任何人都可以解释这个问题。

C：\ Users \ Adam \ Documents \ Ceaser Cipher Dr X \ First try.c || in function＆＃39; main＆＃39;：|

C：\ Users \ Adam \ Documents \ Ceaser Cipher Dr X \ First try.c | 65 | error：函数参数太少＆＃39;解密＆＃39; |

C：\ Users \ Adam \ Documents \ Ceaser Cipher Dr X \ First try.c | 21 | note：声明在这里|

C：\ Users \ Adam \ Documents \ Ceaser Cipher Dr X \ First try.c | 71 | error：功能参数太少＆＃39;加密＆＃39; |

C：\ Users \ Adam \ Documents \ Ceaser Cipher Dr X \ First try.c | 6 | note：声明在这里|

|| ===构建失败：2个错误，0个警告（0分钟，0秒（秒））=== |

编辑：我已更正了我的代码，但现在用户输入了密码字符串后，程序将自动终止。

Answer 1

删除函数头中的int i，并声明为局部变量：

void encrypting(char cipher[25], int shift, int num)
{
        int i;
        for ( i=0; i < num; i++)
        {
                if (cipher[i] >= 'A' && cipher[i] <= 'Z')
                {
                        cipher[i] = (char)(((cipher[i] + shift - 'A' + 26) % 26) + 'A');
                }
                else if (cipher[i] >= 'a' && cipher[i] <= 'z')
                {
                        cipher[i] = (char)(((cipher[i] + shift - 'a' + 26) % 26) + 'a');
                }
        }
}

void decrypting(char cipher[25], int shift, int num)
{
        int i;
        for ( i=0; i < num; i++)
        {
                if (cipher[i] >= 'A' && cipher[i] <= 'Z')
                {
                        cipher[i] = (char)(((cipher[i] - shift - 'A' + 26) % 26) + 'A');
                }
                else if (cipher[i] >= 'a' && cipher[i] <= 'z')
                {
                        cipher[i] = (char)(((cipher[i] - shift - 'a' + 26) % 26) + 'a');
                }
        }
}

Answer 2

您的加密和解密功能在传入3个参数时需要4个参数。

Answer 3

你的两个函数（加密和解密）得到四个参数，但你在代码中传递三个参数

Answer 4

你在函数中缺少一个参数。错误描述是不言自明的。

使用3个args而不是所需的4个

Answer 5

由于解密函数有4个参数，所以你必须传递四个参数，你只是在解密函数中传递3个参数。

C代码不会执行

5 个答案: