我正在开发一个php项目,我希望使用PHP以下列方式显示数据。
因此,当它'X'
天时,PHP将显示某个div元素的内容及其CSS效果。
这里的例子是变量/ info:
Title : What to Eat ?
Monday - eggs, bread, turkey <br/>
Tuesday - oats, rye, wheat bread<br/>
Wednesday - Milk , chicken, fish<br/>
注意:我希望按照Indian standard time [IST]
所以当这一天是Monday
时,
它将显示如下:
What to Eat ?<br/>
eggs, bread, turkey
[this will be the content of monday and css will be used for styling it in div]
当它的tuseday显示时:
What to Eat ?<br/>
oats, rye, wheat bread
星期三它将显示:
What to Eat ?<br/>
Milk , chicken, fish
我如何实现上述请帮助我,使用什么PHP代码,或者是一个更简单的方法。
我希望整整一周显示[Mon -Sunday]
答案 0 :(得分:1)
您可以在此操作中使用数组。以此为例:
<?php
$food = array(
'Monday' => 'Eggs, Bread, Turkey',
'Tueday' => 'Oats, Rye, Wheat Bread',
'Wednesday' => 'Milk, Ckicken, Fish',
'Thursday' => 'Eggs, Bread, Turkey',
'Friday' => 'Oats, Rye, Wheat Bread',
'Saturday' => 'Milk, Ckicken, Fish',
);
// use date function, then you can use this as a 'key' on the array
$day_today = date('l');
?>
<!-- HTML -->
<p>What do eat</p>
<p><?php echo $food[$day_today]; ?></p>
答案 1 :(得分:0)
使用PHP DATE()
这样的事情<?php
date_default_timezone_set('Asia/Kolkata');
$day = date("l");
if( $day == "Monday" ){
echo "<div>Some content for monday</div>";
} else if($day == "Tuesday" ){
echo "<div>Some content for Tuesday</div>";
} else if($day == "Wednesday" ){
echo "<div>Some content for Wednesday</div>";
}
?>