Question

我尝试使用HTML，PHP和MYSQL从数据库中提取数据并将其显示在表单中（稍后进行编辑）。在这一点上，我只是试图提取数据并以表格形式显示。（我后来担心更新）。我拉数据但我的文本框中没有显示任何内容：

<?php 
$con = mysqli_connect("XXXXX");   //removed for privacy

if (mysqli_connect_errno())
{
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
}

$query="select * from VOLUNTEER";
echo '$query';
$result = mysqli_query($con, $query);

echo "<table>";

if ($result)                                   
{                        
    while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) 
{
    echo '<form method = "post" action="insertvolunteer.php">';
    echo '<tr>';
    echo '<td>First Name:</td>';
    echo '<td>' . '<input type=text name=FirstName' . $row["FirstName"] . '</td>';
    echo '<td>' . '<input type=hidden name=VolunteerId' . $row["VolunteerId"] .  '</td>';
echo '</tr>';
}
}
 echo "</form>";
 echo "</table>";                             
 mysqli_close($con);
 ?>

Answer 1

文本框数据需要在value上显示为

echo '<td><input type="text" name="FirstName" value="'.$row["FirstName"].'"></td>';

Answer 2

<强> connect.php

<?php

$server = "server";
$user = "user";
$password = "password";
$bd = "yourbd";

$connect = mysql_connect($server, $user, $password);
$connect = mysql_select_db("$bd", $connect);

if  (!$connect){
echo mysql_error(); exit;
}

?>

<强> namefile.php

<?php
include('connect.php');

    $select = mysql_query("select * from VOLUNTEER");

    while ($show  = mysql_fetch_assoc($select)):

    echo "<table>";
    echo "<form method = 'post' action='insertvolunteer.php'>";
     echo '<tr>';
    echo '<td>First Name:</td>';
    echo '<td><input type="text" name="FirstName" value="'.$show["FirstName"].'"></td>';
    echo '<td><input type="text" name="FirstName" value="'.$show["VolunteerId"].'"></td>';
    echo '</tr>';
    echo "</form";
    echo "</table>";

    endwhile;

?>

创建MySQL查询时，需要声明这一点。怎么样？

$ var =“SELECT * FROM SOMEWHERE”;的错

$ var = mysql_query（“SELECT * FROM SOMEWHERE”）;的右
echo '<td>' . '<input type=text name=FirstName' . $row["FirstName"] . '</td>';中的
'n，您需要关闭代码。而且也不需要单独<td> <input>。

尝试类似的事情：）

@update 我意识到你已经得到了所希望的东西。欢呼声。

获取要在表单中显示的数据

2 个答案: