Question

所以这是我的模特：

CompetitionSchema = new Mongoose.Schema
name :
  type : String
  required : true
required_teams :
  type : Number
teams : [
  _team :
    type : Mongoose.Schema.ObjectId
    ref : 'teams'
  weight :
    type : Number
    min : 0
]

我希望能够填充竞赛对象以访问我已尝试过以下内容的competition.teams[0]._team._id：

  models('Competition')
  .findById id
  .populate('teams._team')
  .exec (error, competition) ->
    if error || !competition
      error_callback error
    else
      success_callback competition

然而这没有效果。我也试过了：

  models('Competition')
  .findById id
  .exec (error, competition) ->
    if error || !competition
      error_callback error
    else
      options = [
        path : 'teams._team'
        model : 'teams'
      ]
      models('Competition')
      .populate(
        competition
      , options
      , (error, competition) ->
          if error || !competition
            error_callback competition
         else
            success_callback competition
      )

也没有效果。我发现API documentation for Model.populate非常令人困惑，所以请原谅我，如果它显然很明显！

Answer 1

在将自己沉浸在主题中之后，我可以更好地了解下面的内容：

  models('Competition')
  .findById id
  .exec (error, competition) ->
    if error || !competition
      error_callback error
    else
      options = [
        path : '_team'
        model : 'teams'
      ]
      models('Team')
      .populate(
        competition.teams
      , '_team'
      , (error, competition_teams) ->
          if error || !competition_teams
            error_callback competition
         else
            success_callback competition
      )

归结为：而不是打电话

Competition.populate(competition, { path : 'teams._team' } , callback);

我现在正在打电话：

Team.populate(competition.teams, '_team', callback);

这有利于修改competition.teams数组而不是返回副本，因此原始competition对象也会收到更改！

填充嵌套的ObjectRef

1 个答案: