Question

我有一张体操结果表，其中只记录了各个器械分数，因此我使用SUM来创建总分。显然我可以对此进行排序，但我真的想根据每个体操运动员的整体得分值为“排名/位置”添加一个额外的列，而不得不求助于PHP中的进一步处理。我也希望每个设备都有一个“等级/位置”！：）

以下是我的“结果”表中的一些示例数据：

+---------+--------------+-------+
| gymnast | apparatus_id | score |
+---------+--------------+-------+
| Isla    |            1 | 12    |
| Isla    |            2 | 10.4  |
| Isla    |            3 | 11.5  |
| Bethany |            1 | 11.5  |
| Bethany |            2 | 10    |
| Bethany |            3 | 11    |
| Anna    |            1 | 12    |
| Anna    |            2 | 13    |
| Anna    |            3 | 10.25 |
+---------+--------------+-------+

然后我有一个类似下面的MySQL查询，将每个设备结果合并为每个体操运动员的一个列并创建总分：

SELECT r.gymnast, app1.score AS app1_score, app2.score AS app2_score, app3.score AS app3_score, ROUND(app1.score+app2.score+app3.score, 2) AS overall_score
FROM (results r)
JOIN apparatuses a ON a.id = r.apparatus_id
LEFT JOIN results app1 ON app1.gymnast_id = r.gymnast_id AND app1.apparatus_id=1
LEFT JOIN results app2 ON app2.gymnast_id = r.gymnast_id AND app2.apparatus_id=2
LEFT JOIN results app3 ON app3.gymnast_id = r.gymnast_id AND app3.apparatus_id=3
GROUP BY r.gymnast
ORDER BY overall_score desc

所以现在我被卡住了，我怎么能在这个查询的基础上为每个设备和整体添加一个等级/位置？

+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+
| gymnast | app1_score | app1_pos | app2_score | app2_pos | app3_score | app3_pos | overall_score | overall_pos |
+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+
| Isla    | 12         | 1        | 10.4       | 2        | 11.5       | 1        | 33.9          | 2           |
| Bethany | 11.5       | 2        | 10         | 3        | 11         | 2        | 32.5          | 3           |
| Anna    | 12         | 1        | 13         | 1        | 10.25      | 3        | 35.25         | 1           |
+---------+------------+----------+------------+----------+------------+----------+---------------+-------------+

如果有人想要玩游戏，那么这里有一个SQL小提琴，其中包含一些示例数据（http://sqlfiddle.com/#!2/2e251e）。：）

Answer 1

以下查询将为您提供排名明智的gymnast_id，然后您可以加入您当前的查询

select gymnast_id,total_score, @curRank := @curRank + 1 AS rank
FROM      
(select gymnast_id,sum(score) as total_score from tablename group by gymnast_id)p, (SELECT @curRank := 0) r
ORDER BY  total_score desc;

对MySQL在MySQL中创建的总分进行排名

1 个答案: