Ajax：如何返回XML数据而不是响应文本

Question

正如您将注意到我的代码，我将使用responseText返回数据。我想将其作为XML数据返回：

//Request is a flickr URL with user entered search terms:
function sendRequest (request) {

    x = new XMLHttpRequest();
    x.open("GET", request,true);


    x.onreadystatechange = function () {



        if (x.readyState==4 && x.status==200){
            //The data is returned as text and added to the page:
            document.getElementById("resultsContainer").innerHTML="success: Raw JSON data below <br> <br>"+x.responseText;

            document.getElementById("getIms").value = "Find Images";
            document.getElementById("getIms").style.background="white";
        } else if (x.status == 404){
            document.getElementById("resultsContainer").innerHTML="Not Found";
        }



    }
    x.send();

}

页面上返回并显示的值类似于：

jsonFlickrApi({"photos":{"page":1,"pages":476982,"perpage":1,"total":"476982","photo":[{"id":"14021160561","owner":"91285504@N05","secret":"dd4f545e17","server":"2920","farm":3,"title":"barack-obama-painting","ispublic":1,"isfriend":0,"isfamily":0}]},"stat":"ok"})

我需要能够使用它来提取照片信息以构建要在屏幕上显示的图像URL。但根据我的理解，我需要使用responseXML而不是responseText来返回值。

我尝试过responseXML，但它让我回来了。