Question

我有一个像下面这样的大文件，我想把这个文件分成多个文件。在ENDMDL之后，每个文件都应该中断。对于以下文件，将有三个名为pose1.av，pose2.av和pose3.av。

的输出文件

MODEL        1
SML    170  O   PRO A  17      16.893   3.030   0.799  1.00  1.00           O
SML    171  OXT PRO A  17      18.167   2.722   2.597  1.00  1.00           O
TER     172      PRO A  17
ENDMDL
MODEL        2
SML      4  CG  ARG A   1      -2.171  -7.105  -4.278  1.00  1.00           C
SML      5  CD  ARG A   1      -1.851  -8.581  -4.022  1.00  1.00           C
SML    113  HD1 HIS A  12       2.465  -8.206   5.062  1.00  1.00           H
TER     114      HIS A  12
ENDMDL
MODEL        3
SML    101  N   HIS A  12       3.765  -3.995   7.233  1.00  1.00           N
SML    102  CA  HIS A  12       2.584  -4.736   6.934  1.00  1.00           C
TER     103      HIS A  12
ENDMDL

Answer 1

使用bash和sed非常有效：

n=0
while IFS= read -r firstline; do
    { echo "$firstline"; sed '/^ENDMDL$/q'; } > "pose$((++n)).av"
done < file

它比其他Bash答案更有效：输出文件只打开一次，大部分解析都是由sed完成的，而不是由bash完成。

Answer 2

csplit可以开箱即用

csplit -z -s -f pose -b "%01d.av" file '/^ENDMDL$/+1' '{*}'

Answer 3

Awk是完成这项任务的不错选择：

awk '{file="pose"++i;printf "%s%s",$0,RS > file;close(file)}' RS='ENDMDL\n' file

Answer 4

使用perl one-liner

perl -ne '$fh or open $fh, "> pose".++$i".av"; print $fh $_; undef $fh if /^ENDMDL/' file.txt

Answer 5

纯粹的Bash：

cnt=1
while read line; do
    echo "$line" >> pose${cnt}.av
    [ "$line" == "ENDMDL" ] && let cnt+=1
done < filename.txt

Answer 6

awk '/^MODEL/{out="pose"++cnt".av"} {print > out}' file

将一个文件拆分为多个文件

6 个答案: