Question

我设置了一个非常简单的烧瓶应用程序来测试CentOS 6上的Apache部署，但是我收到了以下错误：

[Sat Apr 26 12:44:20 2014] [error] mod_wsgi (pid=29782): Target WSGI script '/var/www/html/sites/rtdsllc/rtdsllc.wsgi' cannot be loaded as Python module.
[Sat Apr 26 12:44:20 2014] [error] mod_wsgi (pid=29782): Exception occurred processing WSGI script '/var/www/html/sites/rtdsllc/rtdsllc.wsgi'.
[Sat Apr 26 12:44:20 2014] [error] Traceback (most recent call last):
[Sat Apr 26 12:44:20 2014] [error] File "/var/www/html/sites/rtdsllc/rtdsllc.wsgi", line 10, in <module>
[Sat Apr 26 12:44:20 2014] [error]     from rtdsllc import app as application
[Sat Apr 26 12:44:20 2014] [error] ImportError: cannot import name app

这是我的wsgi文件：

activate_this = '/var/www/virtualenvs/default/bin/activate_this.py'
execfile(activate_this, dict(__file__=activate_this))

path = '/var/www/html/sites/rtdsllc'

import sys
if path not in sys.path:
    sys.path.append(path)

from rtdsllc import app as application

这是我的虚拟主机配置：

WSGISocketPrefix run/wsgi

<VirtualHost *:8086>

    WSGIDaemonProcess rtdsllc user=apache group=apache threads=5
    WSGIScriptAlias /test /var/www/html/sites/rtdsllc/rtdsllc.wsgi

    ErrorLog logs/rtdsllc-error_log
    CustomLog logs/rtdsllc-access_log common

    <Directory /var/www/html/sites/rtdsllc/rtdsllc>
        WSGIProcessGroup rtdsllc
        WSGIApplicationGroup %{GLOBAL}
        Order deny,allow
        Allow from all
    </Directory>
</VirtualHost>

这是我的烧瓶应用程序：

from flask import Flask, render_template

app = Flask(__name__)      

@app.route('/')
def home():
  return render_template('index.html')

if __name__ == '__main__':
  app.run(debug=False)

最后这是我的文件夹结构：

rtdsllc/
├── rtdsllc
│   ├── __init__.py
│   ├── routes.py
│   ├── static
│   │   ├── css
│   │   ├── img
│   │   └── js
│   └── templates
│       ├── base.html
│       └── index.html
└── rtdsllc.wsgi

是什么给出的？我尝试了各种设置组合无济于事。在apache中设置Flask应用程序的正确方法是什么？

修改

ls -las rtdsllc/rtdsllc：

4 drwxr-xr-x. 4 apache apache 4096 Apr 26 13:07 .
4 drwxr-xr-x. 3 apache apache 4096 Apr 25 22:54 ..
0 -rw-r--r--. 1 apache apache    0 Apr 25 20:57 __init__.py
4 -rw-r--r--. 1 apache apache  134 Apr 25 22:55 __init__.pyc
4 -rw-r--r--. 1 apache apache  190 Apr 26 12:48 routes.py
4 -rw-r--r--. 1 apache apache  521 Apr 26 13:07 routes.pyc
4 drwxr-xr-x. 5 apache apache 4096 Apr 25 20:14 static
4 drwxr-xr-x. 2 apache apache 4096 Apr 25 20:19 templates

Answer 1

在做：

from rtdsllc import app as application

它将导入：

rtdsllc/rtdsllc/__init__.py

根据您的目录列表：

0 -rw-r--r--. 1 apache apache    0 Apr 25 20:57 __init__.py

该文件为空，并且没有'app'对象可以通过导入拖入。

以下是哪个文件？

app = Flask(__name__)

现在它不在您尝试从中导入的地方。

更新1

使用：

from rtdsllc.routes import app as application

如果'app'对象位于'rtdsllc.routes'。

在Apache上运行Flask - CentOS

1 个答案: