Question

我有一张表格

http://s12.postimg.org/5lylvp2h9/Untitled.png

表产品

+----+---------------+
| id | product       |
+----+---------------+
|  1 | pencil        |
|  2 | Eraser        |
|  3 | Brush         |
|  4 | teddy bear    |
|  5 | panda         |
|  6 | kaleidoscope  |
+----+---------------+

表供应商

+----+------------------+
| id | Suppliers        |
+----+------------------+
|  1 | Silberauto , Ltd.|
|  2 | MADATA , Ltd.    |
|  3 | Omnitel , Ltd.   |
|  4 | Profito IT Ltd.  |
|  5 | Arfix , Ltd.     |
+----+------------------+

table product_supplier

+------------+-------------+-----------+
| product_id | supplier_id | unit_cost |
+------------+-------------+-----------+
|          4 |           1 |     10.50 |
|          2 |           5 |     15.25 |
|          1 |           2 |     20.40 |
|          3 |           3 |     25.75 |
|          5 |           3 |     30.00 |
|          5 |           4 |     35.75 |
|          1 |           1 |     40.55 |
|          4 |           3 |     45.75 |
|          2 |           2 |     50.15 |
|          3 |           5 |     55.10 |
|          6 |           2 |     60.00 |
|          9 |           2 |     65.55 |
|          7 |           4 |     70.85 |
|          9 |           3 |     75.35 |
|          8 |           1 |     80.20 |
+------------+-------------+-----------+

在我的表单选择字段中，我从表产品中选择一个项目（铅笔）。每个项目都有一个唯一值，该值引用了商品ID（表格产品 - ＆gt; ID ）。

在广播中选择我选择供应商（来自表供应商）。单选按钮具有值（在此示例中为MADATA,UAB）和名称（在此示例中为项目ID 7）

在下一个字段价格中，我想从表格unit_cost打印product_suplier product_id（来自选择字段的value。）等于supplier（来自表suppliers）。

kaina.php 我的情况

SELECT unit_cost 
FROM product_supplier, suppliers
WHERE  product_id= :product_id AND suppliers.suppliers = :suppliers');

$stmt->execute(array('supplier' => $supplier,'product_id' => $product_id));

while($row = $stmt->fetch()) {
    echo $row['unit_cost']." LT ";
}

很糟糕。在此示例中，它打印两个值。如何将SELECT条件更改为一个值，而不是两个（因为有两个销售相同项目的供应商）。

我的代码：

的index.php

<?
$username='root';
$password='pass';
try {
    $conn = new PDO('mysql:host=localhost;dbname=univer', $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    echo 'KLAIDA: ' . $e->getMessage();
}?>

<html>
  <head>
  <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
   <link rel='stylesheet' type= 'text/css' href='css/styles.css'>
   <link rel='stylesheet' type= 'text/css' href='css/bootstrap.css'>

 <script>

 function tiekejai(tiekejas){
      $.ajax({
        type: "POST",
        url: "tiekejai.php?q="+supplier,
        dataType: "html",             
        success: function(duomenys){                    
            $("#tiekejai").html(duomenys); 
        }
    });
};

function kaina(tiekejas,data){
      $.ajax({
        type: "POST",
        url: "kaina.php?supplier="+supplier+"&product_id="+data,

        dataType: "html",             
        success: function(duomenys){                    
            $("#kaina").html(duomenys); 
        }
    });
};

</script>
</head>
<body>

<main id="content" role="content">
 <div id="forma">
<form class="form-horizontal">
<fieldset>  

<legend>Uzsakymo forma</legend>

<div class="control-group">
  <label class="control-label" for="selectbasic">Pasirinkite preke</label>
  <div class="controls">
    <select id="selectas" name="selectas" class="input-xlarge" 
    onchange="tiekejai(this.value)">       
  <?php 

    $data = $conn->query('SELECT * FROM products
                  INNER JOIN product_suplier
              ON products.id = product_suplier.product_id
              GROUP BY product');

    foreach($data as $row) {
        echo "<option value=".$row['product_id'].">".$row['product']."</option>";
    }
  ?> 
    </select>
  </div><!--.controls -->
</div><!--.control-group -->

<div class="control-group">
  <label class="control-label" for="radios">Pasirinkite tiekeja</label>
  <div class="controls" id="tiekejai">

  </div>
</div>

<div class="control-group">
  <label class="control-label" for="radios">kaina</label>
  <div class="controls">

<span class="uneditable-input" id="kaina">Prekes kaina</span>
  </div>
</div>

<div class="control-group">
  <label class="control-label" for="textinput">Kiekis</label>
  <div class="controls">
    <input id="textinput" name="textinput" placeholder="max 40" class="input-xlarge" type="text">
  </div>
</div>

<div class="control-group">
  <label class="control-label" for=""></label>
  <div class="controls">
    <button id="" name="" class="btn btn-primary">Uzsakyti</button>
  </div>
</div>
</fieldset>
</div>
</main>
  <script>
  document.getElementById("selectas").selectedIndex = -1;
  </script>
</body>
</html>

tiekejai.php

<?php

$q=$_GET["q"];

$con = mysql_connect('localhost', 'root', 'pass');
if (!$con){
 die('Could not connect: ' . mysql_error());}

mysql_select_db("univer", $con);

$sql="  SELECT * FROM suppliers
    INNER JOIN product_suppliers
    ON tiekejai.id = product_suppliers.product_id
    WHERE product_suppliers.product_id= '".$q ."'";
$result = mysql_query($sql);

while($row = mysql_fetch_array($result)){

       echo "<label class='radio'>";
       echo  "<input name='". $q ."' id=radios  
       value= '". $row['supplier'] ."'
        type='radio' onchange='kaina(this.value,this.name)'>";
       echo $row['supplier'];
       echo "</label>";
}
mysql_close($con);


?>

kaina.php

<?php
$supplier = $_GET['supplier'];
$product_id = $_GET['product_id'];

$username='root';
$password='pass';
try {
    $conn = new PDO('mysql:host=localhost;dbname=univer', $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

    $stmt = $conn->prepare('

       SELECT unit_cost 
       FROM product_supplier, suppliers
       WHERE  product_id= :product_id AND suppliers.suppliers = :suppliers');

$stmt->execute(array('supplier' => $supplier,'product_id' => $product_id));

while($row = $stmt->fetch()) {
    echo $row['unit_cost']." LT ";
    }  
  } 
 catch(PDOException $e) {
    echo 'KLAIDA: ' . $e->getMessage();
}
?>

Answer 1

我认为从立陶宛语到英语的来回往往让你和我们感到困惑。我们现在可以用英语做整件事吗？所以数据集可能看起来像这样......

products
+----+---------------+
| id | product       |
+----+---------------+
|  1 | pencil        |
|  2 | Eraser        |
|  3 | Brush         |
|  4 | teddy bear    |
|  5 | panda         |
|  6 | kaleidoscope  |
+----+---------------+

suppliers
+----+------------------+
| id | Suppliers        |
+----+------------------+
|  1 | Silberauto , Ltd.|
|  2 | MADATA , Ltd.    |
|  3 | Omnitel , Ltd.   |
|  4 | Profito IT Ltd.  |
|  5 | Arfix , Ltd.     |
+----+------------------+

product_supplier
+------------+-------------+-----------+
| product_id | supplier_id | unit_cost |
+------------+-------------+-----------+
|          4 |           1 |     10.50 |
|          2 |           5 |     15.25 |
|          1 |           2 |     20.40 |
|          3 |           3 |     25.75 |
|          5 |           3 |     30.00 |
|          5 |           4 |     35.75 |
|          1 |           1 |     40.55 |
|          4 |           3 |     45.75 |
|          2 |           2 |     50.15 |
|          3 |           5 |     55.10 |
|          6 |           2 |     60.00 |
|          9 |           2 |     65.55 |
|          7 |           4 |     70.85 |
|          9 |           3 |     75.35 |
|          8 |           1 |     80.20 |
+------------+-------------+-----------+

注意：我删除了product_supplier表上的id列，因为它似乎没有用处。现在，问题是什么？

PHP / MySql从两个不同的表中获取值

1 个答案: