我的应用程序中有webview,我希望它在单击webview中的链接时打开弹出窗口。我添加了以下代码,但它没有工作: -
WebSettings webSettings = webViewPage.getSettings();
webSettings.setJavaScriptEnabled(true);
webSettings.setSupportMultipleWindows(true);
webSettings.setJavaScriptCanOpenWindowsAutomatically(true);
弹出窗口应该像这样显示
答案 0 :(得分:20)
经过3年的漫长岁月后,我回答了自己的问题:
当在网页内触摸链接时,根据网页实施,有两种可能的情况: 1)链接将在同一窗口中打开。 2)链接将在新窗口中打开。
使用以下代码很容易处理第一种情况:
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
在WebViewClient实现中覆盖shouldOverrideUrlLoading将在同一窗口中打开链接。
现在让我们看看第二种情况,其中网页请求在新窗口中打开网址。对于这种情况,我们需要告诉我们的webview支持多个窗口,如下所示:
webView.getSettings().setSupportMultipleWindows(true);
然后将新的网络Chrome客户端添加到网页视图,以便在网页请求新窗口时获取活动
webView.setWebChromeClient(new WebChromeClient() {
@Override
public boolean onCreateWindow(WebView view, boolean isDialog,
boolean isUserGesture, Message resultMsg) {
WebView newWebView = new WebView(WebpageActivity.this);
newWebView.getSettings().setJavaScriptEnabled(true);
newWebView.getSettings().setSupportZoom(true);
newWebView.getSettings().setBuiltInZoomControls(true);
newWebView.getSettings().setPluginState(PluginState.ON);
newWebView.getSettings().setSupportMultipleWindows(true);
view.addView(newWebView);
WebView.WebViewTransport transport = (WebView.WebViewTransport) resultMsg.obj;
transport.setWebView(newWebView);
resultMsg.sendToTarget();
newWebView.setWebViewClient(new WebViewClient() {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
});
return true;
}
}
});
干杯!!!
答案 1 :(得分:2)
将此行添加到您的网络视图 web.addJavascriptInterface(新的Jscalls(this),“Android”);
然后将此行添加到您在网页视图中加载的html中的href href =“javascript:showAndroidToast('要显示的数据或要显示数据的网址')”
public class Jscalls {
Context mContext;
Jscalls(Context c) {
mContext = c;
}
/** Show a toast from the web page */
@JavascriptInterface
public void showToast(final String toast) {
// Toast.makeText(mContext, toast, Toast.LENGTH_SHORT).show();
if (NetworkConnection.isConnected(mContext)) {
((Activity)mContext).runOnUiThread(new Runnable() {
public void run() {
dialog = new Dialog(mContext);
dialog.setTitle("Title");
dialog.setContentView(R.layout.dialog);
dialog.setCancelable(true);
// there are a lot of settings, for dialog, check them all out!
// set up text
WebView web = (WebView) dialog.findViewById(R.id.webVie);
web.getSettings().setJavaScriptEnabled(true);
/*web.clearHistory();
web.clearFormData();
web.clearCache(true);*/
web.setWebViewClient(new HelloWebViewClient());
web.setOnLongClickListener(new OnLongClickListener() {
@Override
public boolean onLongClick(View v) {
return true;
}
});
web.setLongClickable(false);
try{
web.loadUrl(Url.mainUrl
+ toast);//Url to load data from in pop-up
}catch (Exception e) {
// TODO: handle exception
//e.printStackTrace();
}
// dialog.setContentView(web);
dialog.show();
}
});
//web = null ;
// now that the dialog is set up, it's time to show it
/*
* dialog.setFeatureDrawableResource(Window.FEATURE_LEFT_ICON,
* R.drawable.ic_launcher);
*/
// dialog.setFeatureDrawable
} else {
LoginMainActivity.validateEmail("Alert!!",
"This feature requires wi-fi or internet connection.",
mContext);
}
}
private class HelloWebViewClient extends WebViewClient {
@Override
public boolean shouldOverrideUrlLoading(WebView view, String url) {
view.loadUrl(url);
return true;
}
}
Dialog dialog;
}
答案 2 :(得分:0)
如果某人正面临着诸如pop不能打开的问题,或者当您尝试打开js在网络视图中弹出时黑屏。请尝试更改WebView的高度和宽度,例如:-
android:layout_width="fill_parent"
android:layout_height="fill_parent"
OR
android:layout_width="match_parent"
android:layout_height="match_parent"
像这样:-
<WebView
android:id="@+id/web_view"
android:layout_width="match_parent"
android:layout_height="match_parent">