清空listgrid记录原因

时间:2014-04-26 05:41:27

标签: gwt smartgwt smartgwt-pro

我的客户端代码如下所示,我将一些数据发送到服务器以打印出输出。但是当它从服务器返回时,我得到一个空的listgrid记录。造成这种情况的原因是什么。

以下是问题的屏幕截图

enter image description here

if (fieldName.equals("Approve"))
{
IButton button = new IButton();
button.setHeight(18);
button.setWidth(65);
button.setTitle("Approve");
button.addClickHandler(new ClickHandler()
{
    public void onClick(ClickEvent event)
    {
        DebugTools.print("SOID " + record.getAttribute("supplierOrderID") + " SODID" + record.getAttribute("sodID")+" sordID "+record.getAttribute("sordID"));
        approveProduct(record.getAttribute("supplierOrderID"), record.getAttribute("sodID"),record.getAttribute("sordID"));
    }

private void approveProduct(String supplierOrderID, String sodID, String sordID)
{
    Record record = new Record();
                                record.setAttribute("supplierOrderID", supplierOrderID);
                                record.setAttribute("sodID", sodID);
                                record.setAttribute("sordID",sordID);
                                historyGrid.addData(record, callback);

}

          DSCallback callback = new DSCallback()
{
    @Override
    public void execute(DSResponse response, Object rawData, DSRequest request)
    {
        Record[] records = response.getData();

        if (records != null && records.length > 0)
        {
                             Record record = records[0];
                             JavaScriptObject js = record.getJsObj();                            JSONObject json = new JSONObject(js);                          System.out.println("  records.length    " + records.length);                    for (int i = 0; i < records.length; i++)    {                       Record recordd = records[i];
                                            JavaScriptObject jss = recordd.getJsObj();
                                            JSONObject jsonn = new JSONObject(jss);
                                            System.out.println(jsonn.toString());
                                        }
                                    }
                                }
                            };

在服务器端,我的add方法现在非常简单,我只是打印从客户端收到的数据

public DSResponse add(DSRequest dsRequest) throws Exception
{
    DSResponse dsResponse = new DSResponse();
    Long user_idlong = SessionUtills.getSessionUser(dsRequest.getHttpServletRequest());

    System.out.println("sodID       " + dsRequest.getFieldValue("sodID").toString());
    System.out.println("PRODUCT APPROVED !!!!!!!!!!!!!" + " SUPPLIER ORDER ID " + dsRequest.getFieldValue("supplierOrderID").toString());
    return dsResponse;

}

我还附上了问题的镜头

1 个答案:

答案 0 :(得分:0)

问题出在服务器端,您将空DSResponse发送回客户端,因此在客户端,您将获得零长度记录数组。

返回包含新添加记录的所有信息的有效DSResponse


请看一下

必须阅读The basic flow of logic for handling DataSource requests