Question

我目前正在学习使用python进行编程。我正在尝试建立一个基本程序，根据用户输入的数量输出每种类型的硬币（四分之一，镍，一角钱，便士）中的多少。我目前拥有它，因此它将打印0.但是，我希望在print语句中省略这些值。我不确定如何在不制作每个不同的总值并让它们从if语句中打印出来的情况下如何做到这一点。

#for if statement and to ask for what coin number it is
y = 1
#asks user for how many coins 
x = int(input("How much change are you trying to give (in cents)? "))
while(y <= 1):
    q = 25
    d = 10
    n = 5
    p = 1
    #Take total and divide by 25 as many times as you can output as quarter
    totalq = x // 25
    #Take total from that and divide by 10 as many times as you can and output as dime
    totald = (x-(q*(totalq))) // 10
    #Take total from above and divide by 5 as many times as you can and output as nickel
    totaln = (x-(q*(totalq))-(d*(totald))) //5
    #Finally take total from above and see how many is left over and output as penny
    totalp = (x-(q*(totalq))-(d*(totald))-(n*(totaln))) // 1
    y = y + 1
    total = (str(totalq) +" quarters " + str(totald) +" dimes " + str(totaln) +" nickels " + str(totalp) + " pennies")

    print(total)

Answer 1

我认为，最简单的方法是，正如您所建议的那样，使用一堆if s - 类似于：

if totalq:
    print(totalq, "quarters", end=' ')
if totald:
    print(totalq, "dimes", end=' ')
if totaln:
    print(totalq, "nickels", end=' ')
if totalp:
    print(totalq, "pennies")

或者，你可以使用生成器表达式重复一点：

pairs = [(totalq, 'quarters'),
         (totald, 'dimes'),
         (totaln, 'nickels'),
         (totalp, 'pennies')]
total = ' '.join(str(value) + ' ' + name
                 for value, name in pairs
                 if value)
print(total)

就个人而言，我认为后一种方法更漂亮，但它也有点复杂。如果您对后一个代码有所了解，请不要理解，请告诉我。

打印Python函数的特定部分

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