Question

我希望这个图像计时器在5秒后出现，但不知道该怎么做。到目前为止，我已经让图像在表单周围反弹，但我希望图像在5秒后反弹时出现。

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace Bounce
{
    public partial class Form1 : Form
    {

        int horiz, vert, step;

        public Form1()
        {
            InitializeComponent();
        }

        private void timer1_Tick_1(object sender, EventArgs e)
        {
            //image is moved at each interval of the timer

            goblin.Left = goblin.Left + (horiz * step);
            goblin.Top = goblin.Top + (vert * step);


            // if goblin has hit the RHS edge, if so change direction left
            if ((goblin.Left + goblin.Width) >= (Form1.ActiveForm.Width - step))
                horiz = -1;

            // if goblin has hit the LHS edge, if so change direction right
            if (goblin.Left <= step)
                horiz = 1;

            // if goblin has hit the bottom edge, if so change direction upwards
            if ((goblin.Top + goblin.Height) >= (Form1.ActiveForm.Height - step))
                vert = -1;

            // if goblin has hit the top edge, if so change direction downwards
            if (goblin.Top < step)
                vert = 1;
        }


        private void Form1_Load_1(object sender, EventArgs e)
        {
            //Soon as the forms loads activate the goblin to start moving 
            //set the intial direction
            horiz = 1;  //start going right
            vert = 1;   //start going down
            step = 5;
            timer1.Enabled = true;

        }

    }
}

Answer 1

这应该这样做。

using System.Timers; // this is Where the timer class lives.

Timer fiveSecondTimer = new Timer(5000);
fiveSecondTimer.Elapsed += () => { ShowImageHere }; //This is short hand 
fiveSecondTimer.Start();

Answer 2

创建名为startTime的私有变量。启动计时器时，将其值设置为DateTime.Now。每次计时器滴答时，您都可以检查当前DateTime.Now与存储的startTime之间的差异，看看它是否超过5秒。

int horiz, vert, step;
DateTime startTime;

public Form1()
{
    InitializeComponent();
}

private void timer1_Tick_1(object sender, EventArgs e)
{
    var timeElapsed = (DateTime.Now - startTime).TotalSeconds; // Show image if this is greater than 300       
    //image is moved at each interval of the timer

    goblin.Left = goblin.Left + (horiz * step);
    goblin.Top = goblin.Top + (vert * step);


    // if goblin has hit the RHS edge, if so change direction left
    if ((goblin.Left + goblin.Width) >= (Form1.ActiveForm.Width - step))
        horiz = -1;

    // if goblin has hit the LHS edge, if so change direction right
    if (goblin.Left <= step)
        horiz = 1;

     // if goblin has hit the bottom edge, if so change direction upwards
    if ((goblin.Top + goblin.Height) >= (Form1.ActiveForm.Height - step))
        vert = -1;

    // if goblin has hit the top edge, if so change direction downwards
    if (goblin.Top < step)
        vert = 1;

}

private void Form1_Load_1(object sender, EventArgs e)
{
    //Soon as the forms loads activate the goblin to start moving 
    //set the intial direction
    horiz = 1;  //start going right
    vert = 1;   //start going down
    step = 5;
    timer1.Enabled = true;
    timer1.Start();
    startTime = DateTime.Now;
}

Answer 3

我的第一直觉就是说要使用Thread.Sleep（），但我想知道这是否适用于你，因为你似乎不想阻止整个执行5秒钟。

我看到你已经在使用Timer对象来控制这个妖精家伙的游戏循环。有没有任何理由你不能只有另一个具有5秒间隔的计时器，一旦它打勾，就打电话给它以阻止任何未来的嘀嗒事件，并在他的旅途中开始地精？

如何在Microsoft Visual C＃5秒后显示图片？

3 个答案: