Question

我想在Twitter上回应某个帐户关注者的位置列表。我目前得到的结果如下：

Array
(
[users] => Array
    (
        [0] => Array
            (
                [id] => 2247341036
                [id_str] => 2247341036
                [name] => Niall Horan
                [screen_name] => srthoranpayne
                [location] => london      biben
                [description] => My dreams come true
                [url] => 
                [entities] => Array
                    (
                        [description] => Array
                            (
                                [urls] => Array
                                    (
                                    )

                            )

                    )

                [protected] => 
                [followers_count] => 325
                [friends_count] => 641
                [listed_count] => 0
                [created_at] => Sun Dec 15 15:10:06 +0000 2013
                [favourites_count] => 63
                [utc_offset] => 
                [time_zone] => 
                [geo_enabled] => 
                [verified] => 
                [statuses_count] => 223
                [lang] => es
                [status] => Array

 [etc etc]

但我想只有

                [location] => london      biben

在此之后我可以添加的代码可以帮助我吗？我认为它是循环“foreach”的东西，但我不知道如何把它。我该如何修改最后一行？

$url = "https://api.twitter.com/1.1/followers/list.json";
$requestMethod = "GET";
$getfield = '?screen_name='.$visitor.'&count=200';


$twitter = new TwitterAPIExchange($settings);
$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),$assoc = TRUE);
if($string["errors"][0]["message"] != "") {echo "<h3>Sorry, there was a problem.</h3>        <p>Twitter returned the following error message:</p><p><em>".$string[errors][0]["message"]."    </em></p>";exit();}
echo "<pre>";
print_r($string);
echo $string[user]["location"];*/
foreach($string as $items)
  {
   echo "Tweeted by: ".$['user']['location']."<br />";
  }

提前致谢。

编辑：我添加了我已经尝试过的最后一行代码但没有成功。

编辑下面：当前代码。

$url = "https://api.twitter.com/1.1/followers/list.json";
$requestMethod = "GET";
else {$user  = "$visitor";};
$getfield = '?screen_name='.$visitor.'&count=200';


$twitter = new TwitterAPIExchange($settings);
$string = json_decode($twitter->setGetfield($getfield)
->buildOauth($url, $requestMethod)
->performRequest(),$assoc = TRUE);
if($string["errors"][0]["message"] != "") {echo "<h3>Sorry, there was a problem.</h3>                <p>Twitter returned the following error message:</p><p><em>".$string[errors][0]["message"]."        </em></p>";exit();}
echo "<pre>";
print_r($string);
 foreach($data as $items)
  {
    for($i = 0; $i < count($items); $i++) {
    echo "Location: " . $items[$i]['location']. "<br />";
   }
  }

Answer 1

你循环结果如下：

foreach($string as $items)
  {
   echo "Tweeted by: " . $items[0]['location'] . "<br />";
  }

编辑：

这是一个更强大的例子：

$data = Array
    (
    "users" => Array
        (
            "0" => Array
                (
                    "id" => "2247341036",
                    "id_str" => "2247341036",
                    "name" => "Niall Horan",
                    "screen_name" => "srthoranpayne",
                    "location" => "london      biben",
                    "description" => "My dreams come true",
                    "url" => "",
                    "entities" => Array
                        (
                            "description" => Array
                                (
                                    "urls" => Array
                                        (
                                        )

                                )

                        ),

                    "protected" => "",
                    "followers_count" => "325",
                    "friends_count" => "641",
                    "listed_count" => "0",
                    "created_at" => "Sun Dec 15 15:10:06 +0000 2013",
                    "favourites_count" => "63",
                    "utc_offset" => "",
                    "time_zone" => "",
                    "geo_enabled" => "",
                    "verified" => "",
                    "statuses_count" => "223",
                    "lang" => "es",
                    "status" => Array ()
                ),
            "1" => Array
                (
                    "id" => "2247341036",
                    "id_str" => "2247341036",
                    "name" => "Niall Horan",
                    "screen_name" => "srthoranpayne",
                    "location" => "berlin germany",
                    "description" => "My dreams come true",
                    "url" => "",
                    "entities" => Array
                        (
                            "description" => Array
                                (
                                    "urls" => Array
                                        (
                                        )

                                )

                        ),

                    "protected" => "",
                    "followers_count" => "325",
                    "friends_count" => "641",
                    "listed_count" => "0",
                    "created_at" => "Sun Dec 15 15:10:06 +0000 2013",
                    "favourites_count" => "63",
                    "utc_offset" => "",
                    "time_zone" => "",
                    "geo_enabled" => "",
                    "verified" => "",
                    "statuses_count" => "223",
                    "lang" => "es",
                    "status" => Array ()
                )               
            )
        );

  foreach($data as $items)
  {
    for($i = 0; $i < count($items); $i++) {
    echo "Tweeted by: " . $items[$i]['location']. "<br />";
   }
  }

输出：

Location: london biben
Location: berlin germany

编辑：我可能不太清楚，但你必须混合使用foreach和for循环来获得你想要的结果：

  foreach($data as $items)
  {
    for($i = 0; $i < count($items); $i++) {
    echo "Location: " . $items[$i]['location']. "<br />";
   }
  }

现在，您将在数组中前进并获得所需的输出。（：

echo only location Twitter GET API

1 个答案: