请帮助我理解为什么对象没有得到以下代码的持久性。它抛出 javax.persistence.TransactionRequiredException:JBAS011469:执行此操作需要事务(使用事务或扩展持久化上下文)
public class OrganizationRepositoryImpl implements OrganizationRepository {
@PersistenceContext(unitName="usermanagement",type=PersistenceContextType.TRANSACTION)
private EntityManager em;
public void save(Organization organization) {
try {
em.persist(organization);
}catch(Exception e) {
e.printStackTrace();
}
}
}
但如果我使用 @Stateless 注释(现在ejb)注释该类,则对象开始被持久化
@Stateless
public class OrganizationRepositoryImpl implements OrganizationRepository {
@PersistenceContext(unitName="usermanagement",type=PersistenceContextType.TRANSACTION)
private EntityManager em;
public void save(Organization organization) {
try {
em.persist(organization);
}catch(Exception e) {
e.printStackTrace();
}
}
}
的persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://xmlns.jcp.org/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence
http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd"
version="2.1">
<persistence-unit name="usermanagement" transaction-type="JTA">
<jta-data-source>java:jboss/datasources/MysqlXADS</jta-data-source>
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQL5Dialect"/>
<property name="hibernate.hbm2ddl.auto" value="create-drop"/>
<property name="hibernate.show_sql" value="true"/>
<property name="hibernate.format_sql" value="true"/>
<property name="use_sql_comments" value="true"/>
<property name="jboss.entity.manager.factory.jndi.name" value="java:jboss/myEntityManagerFactory" />
</properties>
</persistence-unit>
</persistence>
调用Repository以将对象持久保存到数据库的服务类
public class OrganizationServiceImpl implements OrganizationService {
@Inject
private OrganizationRepository orgRepo;
public Response createOrganization(InputStream is) {
Organization org = null;
org = readStream(is);
orgRepo.save(org);
return Response.created(URI.create("/organizations/" + org.getId()))
.build();
}
private Organization readStream(InputStream is) {
JAXBContext context;
Organization org = null;
try {
context = JAXBContext.newInstance(Organization.class);
Unmarshaller um = context.createUnmarshaller();
org = (Organization) um.unmarshal(is);
} catch (JAXBException e) {
e.printStackTrace();
}
return org;
}
}
答案 0 :(得分:7)
当您将bean声明为@Stateless
时,该bean中的方法默认为transactional。事务方法在完全执行时提交持久性状态。
如果您没有使用@Stateless
方法注释您的类,则默认情况下不是事务性的,因此您会得到上述异常。
答案 1 :(得分:4)
我对EJB并不太熟悉,但我认为问题在于没有@Stateless注释,bean不是EJB,因此不会自动管理事务。如果需要有状态,请使用@Stateful注释创建有状态EJB。如果您不想使用EJB,则必须使用EntityManager手动管理事务。
tx = em.getTransaction();
tx.begin();
// do some work
...
tx.commit();