我正在尝试生成highcharts的双轴,线和柱形图。我已经尝试过stackoverflows sugesstions但我找不到合适的解决方案。我已经正确地格式化了数据但是图表没有生成显示空白。我想要这种类型的[link] http://jsfiddle.net/sunman/dwyNz/8/。在样条线中我想显示' bsp值'在列中我想显示facilities_total。所以下面我展示了这个图的代码。我还在index.php中指出了我的错误。
这是我的 Index.php
$(function () {
$('#container').highcharts({
chart: {
zoomType: 'xy'
},
title: {
text: 'Project faclityv Rating'
},
subtitle: {
text: 'testing'
},
xAxis: [{
categories: []
}],
yAxis: [{ // Primary yAxis
labels: {
// format: '{value} Rs.',
style: {
color: Highcharts.getOptions().colors[1]
}
},
title: {
text: 'Bsp Cost',
style: {
color: Highcharts.getOptions().colors[1]
}
}
}, { // Secondary yAxis
title: {
text: 'facility rating',
style: {
color: Highcharts.getOptions().colors[0]
}
},
labels: {
//format: '{value} out of 100',
style: {
color: Highcharts.getOptions().colors[0]
}
},
opposite: true
}],
tooltip: {
shared: true
},
legend: {
layout: 'vertical',
align: 'left',
x: 120,
verticalAlign: 'top',
y: 100,
floating: true,
backgroundColor: (Highcharts.theme && Highcharts.theme.legendBackgroundColor) || '#FFFFFF'
},
series: [{
name: 'Facility Rating',
type: 'column',
yAxis: 1,
data: [],
tooltip: {
valueSuffix: ' out of 100'
}
}, {
name: 'Bsp Cost',
type: 'spline',
data: [],
tooltip: {
valueSuffix: 'Rs.'
}
}]
});
$.getJSON("combochart.php", function(json) {
options.xAxis.categories = json[0]['data']; /*error here: ReferenceError: options is not defined */
options.series[0] = json[1];
options.series[1] = json[2];
chart = new Highcharts.Chart(options);
});
});
这是我的 combochart.php
$query1 = mysql_query("SELECT projects_detail.Project_name,superfac_rating.faci_total
FROM projects_detail LEFT OUTER JOIN superfac_rating
ON projects_detail.project_id= superfac_rating.project_id ");
$category = array();
$category['name'] = 'Project';
while($row1 = mysql_fetch_array($query1)) {
$category['data'][] = $row1['Project_name'];
$series1['data'][] = $row1['faci_total'];
}
$query2 = mysql_query("SELECT projects_detail.Project_name,superfac_rating.faci_total
FROM projects_detail LEFT OUTER JOIN superfac_rating
ON projects_detail.project_id= superfac_rating.project_id
LEFT OUTER JOIN cost ON gsuperfac_rating.project_id=cost.project_id ");
$series1 = array();
$series1['name'] = 'Project Name';
$series2 = array();
$series2['name'] = 'BSP VALUES';
while($row2 = mysql_fetch_array($query2)) {
$series1['data'][] = $row2['faci_total'];
$series2['data'][] = $row2['bsp'];
}
$result = array();
array_push($result,$category);
array_push($result,$series1);
array_push($result,$series1);
array_push($result,$series2);
print json_encode($result, JSON_NUMERIC_CHECK);
我认为我在json代码中有问题,这就是为什么我无法获取graph.i数据在我的控制台中检查没有错误。但我调试此代码并且json结果显示我(json o / p在jsfiddle中写入)但图形不出现在浏览器中。我在jsfiddle中解释[link] jsfiddle.net/sunman/rDYvt/9请检查一下。给我解决方案我错了。所以请帮助我并解决我的疑问。
答案 0 :(得分:1)
在你的 $。getJSON(" combochart.php",function(json)中,你需要像这样设置setData
theChart.xAxis[0].setCategories(json[0]['data']);
theChart.series[0].setData(json[1]['data'], false);
theChart.series[1].setData(json[2]['data'], true);
答案 1 :(得分:1)
好的,它现在正在运作......
将其粘贴到JSFiddle中以使其正常工作......
$(document).ready(function() {
var json= '[{"name":"Project","data":["Green View","Grand","Arete","Canary Greens","Terra","Beethovens","Ninex City","South Park","Callidora","Lotus","Coban","NCR Green","Kocoon","Estella","NCR One"]},{"name":"Facilities Rating","data":[45,55,55,55,55,55,55,55,55,55,55,55,55,55,55]},{"name":"BSP VALUES","data":[97500,55745,16400,98700,38600,12090,94700,11400,12450,89500,86725,88335,54200,18200,30400]}]'
var jsobj = JSON.parse(json)
var firstSeriesData = [];
var secondSeriesData = [];
jsobj[1].data.forEach(function(seriesOneData){
firstSeriesData.push(seriesOneData);
})
jsobj[2].data.forEach(function(seriesTwoData){
secondSeriesData.push(seriesTwoData);
})
$('#container').highcharts({
chart: {
zoomType: 'xy',
type: 'column',
marginRight: 130,
marginBottom: 50
},
title: {
text: 'Top 12 Projects Facilities Rating and BSP Costs ',
x: -20 //center
},
subtitle: {
text: '',
x: -20
},
xAxis: {
categories: jsobj[0].data
},
yAxis: {
min: 0,
title: {
text: 'Facilities Rating'
},
plotLines: [{
value: 0,
width:1,
color: '#808080'
}]
},
tooltip: {
formatter: function() {
return '<b>'+ this.series.name +'</b><br/>'+
this.x +': '+ this.y;
}
},
plotOptions:{
column: {
stacking: 'normal',
dataLabels: {
enabled: true,
color:'white'
}
}
},
legend: {
layout: 'vertical',
align: 'right',
verticalAlign: 'top',
borderWidth: 0,
x: -10,
y:110
},
series: [ {
name:'Facilities Rating',
data:firstSeriesData,
id:'dataseries'
},{
name:'BSP',
type:'spline',
data:secondSeriesData
}]
})
});
一对评论..你的JSON中有一个身份不明的角色。这是我粘贴你的JSON字符串所得到的。
请注意JSON中间的红点。
另外,请确保按此顺序加载高级图表模块...
<script src="http://code.highcharts.com/highcharts.js"></script>
<script src="http://code.highcharts.com/stock/modules/exporting.js"></script>
<script src="http://code.highcharts.com/modules/exporting.js"></script>
<div id="container" style="min-width: 310px; height: 400px; margin: 0 auto"></div>
最后,你有两个系列,但其中一个的值低于100,另一个的值超过100k。所以第一个系列不会显示,因为它与第二个相比几乎为0。你必须要做点什么。
答案 2 :(得分:0)
在您的函数$.getJSON("combochart.php", function(json)
中,您需要明确定义所需的options
。您也没有真正设置任何数据。我假设json[0]['data']
是一个类别列表,例如['Cat1', 'Cat2',...]
,json[1]
和json[2]
包含[val1, val2, ...]
等数据。如果是这样,你需要做这样的事情:
$.getJSON("combochart.php", function(json) {
var theChart = $('#container').highcharts();
theChart.xAxis[0].setCategories(json[0]['data']); /*error here: ReferenceError: options is not defined */
theChart.series[0].setData(json[1]);
theChart.series[1].setData(json[2]);
//chart = new Highcharts.Chart(options);
});
});