Question

我正在尝试运行此SQL查询：

SELECT * from tickets 
where status = 'Completed' 
and DATE(closed_timestamp) = '2014-04-25' 
group by assigned_to

我想显示状态为“已完成”的行数最多的assigned_to列以及今天closed_timestamp日期

如何确保它显示最多行的assigned_to？

Answer 1

假设“今天”是问题中的日期，这是你想要的吗？

SELECT assigned_to
from tickets 
where status = 'Completed' and DATE(closed_timestamp) = '2014-04-25' 
group by assigned_to
order by count(*) desc
limit 1;

Answer 2

Select Count (whatever your primary key column is) as number 
from tickets where status = 'Completed' and DATE(closed_timestamp) = '2014-04-25' 
group by assigned_to
order by number desc
LIMIT 1;

这将计算具有相同assigned_to值的ID数量，并将其限制为第一个结果。

Answer 3

这样的事情：

select assigned_to, count(*) records
from etc
group by assign_to
order by records desc
limit 1

SQL选择查询以选择最多行

3 个答案: