Question

我使用字段LastName的前三个字符生成字母数字ID，然后使用递增的3位数字。我在MSSQL 2012中使用的查询是：

SELECT LastName, FirstName,
       UPPER(LEFT(LastName, 3)) + LEFT('000', LEN(ROW_NUMBER()
                   OVER (PARTITION BY  LEFT(LastName, 3)ORDER BY LEFT(LastName, 3)) )+1)
      +  CAST(ROW_NUMBER() OVER (PARTITION BY  
               LEFT(LastName, 3)ORDER BY LEFT(LastName, 3))  AS NVARCHAR(1000)) AS ID
FROM @Table

查询工作相对较好但是一旦数字增加到2而不是结束010，它就是00010.一旦数字部分增加到三位数，情况也是如此。例如，我想要一个如下输出：

╔══════════╦═══════════╦══════════╗
║ LastName ║ FirstName ║    ID    ║
╠══════════╬═══════════╬══════════╣
║ Jones    ║ David     ║ JON001   ║
║ Jones    ║ David     ║ JON002   ║
║ Jones    ║ David     ║ JON003   ║
║ Jones    ║ David     ║ JON004   ║
║ Smith    ║ John      ║ SMI001   ║
║ Smith    ║ John      ║ SMI002   ║
║ Smith    ║ Robert    ║ SMI003   ║
║ Smith    ║ John      ║ SMI004   ║
║ Smith    ║ John      ║ SMI005   ║
║ Smith    ║ Robert    ║ SMI006   ║
║ Smith    ║ John      ║ SMI007   ║
║ Smith    ║ John      ║ SMI008   ║
║ Smith    ║ Robert    ║ SMI009   ║
║ Smith    ║ John      ║ SMI010   ║
║ Smith    ║ John      ║ SMI011   ║
║ Smith    ║ Robert    ║ SMI012   ║
║  ..      ║    ..     ║   ..     ║
║ Smith    ║ James     ║ SMI100   ║
╚══════════╩═══════════╩══════════╝

我不确定如何处理递增的数字字段。感谢您提供的任何帮助。

Answer 1

从右边而不是左边？

SELECT *, UPPER(LEFT(LastName, 3)) + RIGHT('000' + CAST(ID AS VARCHAR(3)), 3)
FROM (
    SELECT 
        LastName, 
        FirstName, 
        ROW_NUMBER() OVER (PARTITION BY LEFT(LastName, 3) ORDER BY LastName) AS ID
    FROM @table
) T

Alpha数字ID的格式

1 个答案: