Question

我正在使用以下代码在单独的线程中打开一个窗口

public partial class App : Application
{
    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        Thread newWindowThread = new Thread(new ThreadStart(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));

        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
        // Start the thread
    }
}

如果我在方法中使用此代码，它可以工作。但是当我按如下方式使用它时，我收到一个错误：

public partial class App : Application
{
    #region Instance Variables
    private Thread newWindowThread;

    #endregion

    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        newWindowThread = new Thread(new ThreadStart(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
        // Start the thread
    }
}

它会抛出以下错误：

System.Threading.ThreadStateException
The state of the thread was not valid to execute the operation

这是什么原因？

Answer 1

@ d.moncada，@ JPVenson，@ TomTom对所有人抱歉，特别是@ d.moncada，你的回答让我意识到我的真实错误，确实如果运行一次，直到我的代码工作。但我真正的问题是我试图在两个阶段按下button1_Click，我真的拿了一个用

线调用方法的计时器

 private void button1_Click(object sender, RoutedEventArgs e)

现在问题的解决方案是Detecting a Thread is already running in C# .net?

Answer 2

我认为问题是您在ApartmentState开始运行后设置了Thread。

尝试：

public partial class App : Application
{
    #region Instance Variables
    private Thread newWindowThread;

    #endregion

    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        newWindowThread = new Thread(new Thread(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));
        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        // Start the thread
        newWindowThread.Start();
    }
}

Answer 3

你为什么要这样做？（几乎）没有理由在你的应用程序中运行一个2end UI线程...如果你想要一个非Modal新窗口，请实例化你的窗口并调用show。

为什么差不多？因为这是一个非常复杂的主题，除非你有一个巨大的变化来完全发展这种行为，你可以没有它。

在单独的线程中启动WPF窗口

3 个答案: