Question

我想以相同的格式将以下数组传递给我的receiver类，并以相同的格式获取它，即数组应保持其结构。

 curDts= new String[][] {{"1","2","3"}, {}, {"4","5","6"}};

以下是我到目前为止所尝试的内容，

    Intent intent = new Intent(this, AlarmReceiver.class);
            for(int i = 0; i<curDts.length ; i++){
                for(int j = 0; j<curDts[i].length; j++){
                    intent.putExtra("date"+i,"'"+curDts[i][j]+"',");
                    Log.v("sending","'"+curDts[i][j]+"',");
                }
            }

    for(int i=0; i<12; i++){    
        Log.v("",""+arg1.getExtras().getString("date"+i));
        }

Answer 1

String []是可序列化的对象以及String [] []，这意味着你只需在intent intent.putExtra(key,serializableObject)中使用ready方法，在接收方你可以说intent.getSerializableExtra(KEY);

如果那就是你要找的东西。

<强>被修改

要传递数据，请执行以下操作：

    Object[] objArr = new Object[]{ new String[]{"2"} ,new String[]{"5"}};
    intent.putExtra("dates", objArr);

并挽回他们：

    private BroadcastReceiver mBroadcastReceiver = new  BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {

    Object[] obj = (Object[]) intent.getSerializableExtra("dates");
    if(obj != null){
        for (int i = 0; i < obj.length; i++) {
            String[] object = (String[])obj[i];
            Log.d(getClass().getSimpleName(), "OBJ : " + object[0]);
        }
    }

    }
};

Answer 2

执行此操作的一种方法是将较大数组中的每个String数组编码为String，并通过Intent传递String数组。该String数组可以由接收Intent的Activity解码。

我写了一个可以编码/解码String数组的类，可以在这里找到：https://gist.github.com/liangricha/10759438。

或者，您可以查看序列化。

Answer 3

您可以传递整数，并且可以传递String[]，所以：

int i = 0;
intent.putExtra("size", curDts.length);
for (String[] value : curDts) {
    intent.putExtra("item"+ i++, value);
}

要检索它：

int size = intent.getIntExtra("size", 0);
String[][] curDts = new String[][size];
for (int i = 0; i < size; i++) {
    curDts[i] = intent.getStringArrayExtras('item" + i);
}

Answer 4

// try this way,hope this will help you...
Note : try to use ArrayList<ArrayList<String>> insted of two dimensional which can be easy Serializable.


**FirstActivty**
public class MyActivity extends Activity{

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity1);
        ArrayList<ArrayList<String>> list = new ArrayList<ArrayList<String>>();
        ArrayList<String> first = new ArrayList<String>();
        first.add("1");
        first.add("2");
        first.add("3");

        ArrayList<String> second = new ArrayList<String>();
        second.add("4");
        second.add("5");
        second.add("6");

        ArrayList<String> third = new ArrayList<String>();
        third.add("7");
        third.add("8");
        third.add("9");

        list.add(first);
        list.add(second);
        list.add(third);
        Intent intent =new Intent(this,MyActivity2.class);
        intent.putExtra("SerializableList",list);
        startActivity(intent);
    }

}

**SecondActivity**
public class MyActivity2 extends Activity{

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity2);

        ArrayList<ArrayList<String>> list = (ArrayList<ArrayList<String>>) getIntent().getSerializableExtra("SerializableList");

        for (int i=0;i<list.size();i++){
            ArrayList<String> row = list.get(i);
            for (int j=0;j<row.size();j++){
                System.out.println("ParentIndex >> ChildIndex >> Value "+i+" >> "+j+" >> "+row.get(j));
            }
        }
    }

}

如何将2维数组传递给android中的意图

4 个答案: