如何组合数组并将其转换为字符串?我有两个数组:
a = ["09:00", "10:00", "11:00", "12:00"]
b = ["09:30", "10:30", "11:30", "12:30"]
如何以此格式获取结果字符串?
c = '"09:00" - "09:30", "10:00" - "10:30", "11:00" - "11:30", "12:00" - "12:30"'
答案 0 :(得分:6)
我做:
a = ["09:00", "10:00", "11:00", "12:00"]
b = ["09:30", "10:30", "11:30", "12:30"]
a.zip(b).map { |e1,e2| "\"#{e1}\" - \"#{e2}\"" }.join(', ')
答案 1 :(得分:2)
这应该有效:
a.zip(b).map { |e1, e2| "\"#{e1}\" - \"#{e2}\"" }.join(', ')
答案 2 :(得分:1)
怎么样:
a.zip(b).map { |e1, e2| "'#{e1}' - '#{e2}'" }.join(', ')
答案 3 :(得分:0)
你可以通过以下方式实现这一目标:
a.each_with_index.map {|e,i| "#{e} - #{b[i]}"}
> a = ["09:00", "10:00", "11:00", "12:00"]
=> ["09:00", "10:00", "11:00", "12:00"]
> b = ["09:30", "10:30", "11:30", "12:30"]
=> ["09:30", "10:30", "11:30", "12:30"]
> a.each_with_index.map {|e,i| "#{e} - #{b[i]}"}.join(', ')
=> "\"09:00\" - \"09:30\", \"10:00\" - \"10:30\", \"11:00\" - \"11:30\", \"12:00\" - \"12:30\""