Question

我打算用Java编写一个名为Master Master的游戏。

现在AI从1-6生成4个数字，然后用户必须猜测它。

现在我有20分钟的GUI界面，我正在努力研究如何最好地处理这个和布局的使用。

但我的问题是：

如果随机数是1122，我如何根据用户输入将其与猜测值和输出值进行比较。

例如1122并且用户猜测1133我如何输出RRWW r表示正确的数字和位置而W表示错误？

没有做过太长时间对我这么新。

Answer 1

您可以将int设置为字符串，然后设置为char[]并比较每个值并将它们放入boolean[]数组中，以告知它们是对还是错例如：

boolean[] howManyRight(int number, int guess, int length){
    char[] n = String.valueOf(number).toCharArray();
    char[] g = String.valueOf(guess).toCharArray();
    boolean[] rightAnswers = new boolean[length];        

    for(int i = 0; i < length; i++){
        boolean[i] = n[i] == g[i];
    }

    return rightAnswers;
}

Answer 2

不确定您对Mastermind的熟悉程度，但通常您的示例的结果只是RR。完全不正确的数字在技术上不需要讨论。相反，W可以表示代码中的数字，但是在错误的位置。因此，如果我们稍微更改您的示例（生成的代码仍然可以是1122，但是用户的猜测现在是1234），它将生成R W的结果（1对，在错误的位置1）为了实现这看起来像这样：

public String compareGuessToCode(String guess,String code) {
    //Variable to store result to show the user
    String result = "";
    //Necessary variables for code comparison
    //These xxxCharCount variables are used to keep track of how many of each possible
    // character are used in the guess and the code.
    int[] guessCharCount = new int[6];
    int[] codeCharCount  = new int[6];
    //These variables are used for bookkeeping during the evaluation process
    int   guessCharVal   = 0;
    int   guessValPos    = 0;
    int   codeCharVal    = 0;
    int   codeValPos     = 0;
    //Variables to keep track of perfectly correct and wrong position characters
    int   r              = 0;
    int   w              = 0;
    //Set all positions in xxxCharCount to 0
    for (int i = 0; i < 6; i++) {
        guessCharCount[i] = 0;
        codeCharCount[i]  = 0;
    }
    //Analyze the code
    for (int i = 0; i < code.length(); i++) {
        codeCharVal = (int) code.charAt(i);
        codeValPos  = codeCharVal - 1;
        codeCharCount[codeValPos] += 1;
    }
    //Analyze the guess
    for (int i = 0; i < guess.length(); i++) {
        guessCharVal = (int) guess.charAt(i);
        guessValPos  = guessCharVal - 1;
        //Compare guess characters to code characters
        if (guess.charAt(i) == code.charAt(i)) {
            //Show the position as correct
            r++;
            //Increment the appropriate slot in the character counter
            guessCharCount[guessValPos]++;
        }
    }
    //We want to check if the any guess characters are in the code, but we also want
    //to ensure that we haven't already accounted for all occurrences of the
    //guessed character in the code.
    for (int i = 0; i < guess.length(); i++) {
        guessCharVal = (int) guess.charAt(i);
        if (code.contains(String.valueOf(guess.charAt(i))) && guessCharCount[guessValPos] < codeCharCount[guessValPos]) {
            //Show the character as present, but in the wrong spot
            w++;
            //Increment the appropriate slot in the character counter
            guessCharCount[guessValPos]++;
        }
    }
    //Build the result string...perfect first...
    for (int i = 1; i <= p; i++) {
        if (result.isEmpty()) {
            result += "P";
        } else {
            result += " P";
        }
    }
    //...wrong spot last
    for (int i = 1; i <= p; i++) {
        if (result.isEmpty()) {
            result += "X";
        } else {
            result += " X";
        }
    }
    return result;
}

Java GUI MasterMind

2 个答案: