我是android开发的新手。首先,我使用AsyncTask通过按钮将数据保存在数据库中。而现在我试图在同一活动的其他按钮上调用意图,但是当我点击第二个按钮时没有任何反应。任何人都可以帮助我PLZ ..在这里我也发布了一些代码。
MainActivity.java
//initialize all view objects
et=(EditText)findViewById(R.id.editText1);
AddBtn=(Button)findViewById(R.id.btn_add);
spn = (Spinner) findViewById(R.id.spinner1);
NextBtn=(Button) findViewById(R.id.button1);
SQLcon = new SQLController(this);
// opening database
SQLcon.open();
loadtospinner();
}
public void onClick(View v){
if(v.getId() == R.id.btn_add){
new MyAsync().execute();
}
else {
Intent in=new Intent(Intent, Second.class);
startActivity(in);
}
}
public void loadtospinner() {
Cursor c = SQLcon.readData();
ArrayList<String> al = new ArrayList<String>();
c.moveToFirst();
while (!c.isAfterLast()) {
String name = c.getString(c.getColumnIndex(DBhelper.MEMBER_NAME));
al.add(name);
c.moveToNext();
}
ArrayAdapter<String> aa1 = new ArrayAdapter<String>(
getApplicationContext(), R.layout.spinner_item, R.id.textView1,
al);
spn.setAdapter(aa1);
// closing database
SQLcon.close();
}
private class MyAsync extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
PD = new ProgressDialog(MainActivity.this);
PD.setTitle("Please Wait..");
PD.setMessage("Loading...");
PD.setCancelable(false);
PD.show();
}
@Override
protected Void doInBackground(Void... params) {
String name = et.getText().toString();
// opening database
SQLcon.open();
// insert data into table
SQLcon.insertData(name);
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
loadtospinner();
PD.dismiss();
}
}
}
答案 0 :(得分:1)
改变下面的事情
public class FirstActivity extends Activity implements OnClickListener {
之后在创建
secondButton = (Button) findViewById(R.id.rightButton);
secondButton.setOnClickListener(this);
覆盖以下方法
@Override
public void onClick(View v) { // Parameter v stands for the view that was clicked.
// getId() returns this view's identifier.
if(v.getId() == R.id.leftButton){
// setText() sets the string value of the TextView
changingTextView.setText("You clicked First");
}else if(v.getId() == R.id.rightButton){
changingTextView.setText("You clicked Second");
}
}
答案 1 :(得分:1)
活动中的第一个implements OnClickListener
比setOnClickListener
更像<{1}}
button
现在在 AddBtn=(Button)findViewById(R.id.btn_add);
_AddBtn.setOnClickListener(this);
NextBtn=(Button) findViewById(R.id.button1);
_NextBtn.setOnClickListener(this);
onClick
答案 2 :(得分:0)
您正在传递Intent而不是活动,通过更改此
传递活动Intent in=new Intent(Intent, Second.class);
startActivity(in);
并尝试
Intent in=new Intent(getApplicationContext(), Second.class);
startActivity(in);
希望这项工作