此程序创建一个排序列表,然后插入一个元素,使列表仍然保持排序。我认为逻辑是正确的..但是程序不会打印新形成的列表。这是代码。怎么了?
#include<stdio.h>
#include<malloc.h>
#include<stdlib.h>
struct list {
int number;
struct list *next;
};
typedef struct list node;
void create(node *);
void print(node *);
void sortedInsert(node **);
main() {
int user_response;
node *head;
head = (node *)malloc(sizeof(node));
create(head);
printf("Look at your creation!! A linked list!!1 heheheh...........\n");
print(head);
printf("Do you want to experience some \"sort\" of thrill?\n1 for yes..\n");
scanf("%d",&user_response);
if(user_response == 1) {
sortedInsert(&head);
printf("Look at the marvel of linked list...\n");
print(head);
}
else {
printf("Ha\n tired fellow,lack of ambition!!!\n");
exit(0);
}
return 0;
}
void create(node *head) {
printf("Enter a number,-999 to stop\n");
scanf("%d",&head->number);
if(head->number == -999) {
head->next = NULL;
}
else {
head->next = (node *)malloc(sizeof(node));
create(head->next);
}
}
void print(node *head) {
if(head->next != NULL) {
printf("%d-->",head->number);
print(head->next);
}
else {
printf("%d",head->number);
}
}
void sortedInsert(node **headRef) {
node *new_node;
node *prev_ptr = *headRef;
node *dummy_ptr = *headRef;
int key;
printf("Which value do you wanna insert\n");
scanf("%d",&key);
new_node = (node *)malloc(sizeof(node));
new_node->number = key;
while((*headRef)->next != NULL) {
if((*headRef)->number >= key) {
prev_ptr->next = new_node;
new_node->next = *headRef;
*headRef = dummy_ptr;
}
else {
prev_ptr = *headRef;
*headRef = (*headRef)->next;
}
}