Question

我有与另一个表article_has_type

相关的表格文章

文章表的结构是

    CREATE TABLE `articles` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `titre` VARCHAR(255) NULL DEFAULT NULL,
    `description` TEXT NULL,
)

表article_has_type的结构是

CREATE TABLE `arhastypes` (
    `id` INT(11) NOT NULL AUTO_INCREMENT,
    `article_id` INT(11) NULL DEFAULT NULL,
    `type_id` INT(11) NULL DEFAULT NULL,
)

我想将最后一篇文章添加到每种类型中。

谢谢。

Answer 1

由于id列为AUTO INCREMENT，您可以这样做：

获取articles中的最后一条记录：

SELECT * FROM articles WHERE id=(SELECT MAX(id) FROM articles)

要获取每种类型arhastypes的最后记录的详细信息：

SELECT * FROM arhastypes WHERE id IN 
            (SELECT MAX(id) FROM arhastypes
             GROUP BY type_id)

修改

要从两个表中选择记录，您可以执行以下操作：

SELECT ART.id,ART.titre,ART.description,ARH.id as arhastypes_id,ARH.type_id FROM arhastypes ARH JOIN articles ART ON ARH.article_id=ART.id WHERE ARH.id IN (SELECT MAX(id) FROM arhastypes GROUP BY type_id)

Answer 2

正在寻找这个吗？

Select * from articles where id in (select max(id) from articles)
Select * from arhastypes where id in (select max(id) from arhastypes)

Answer 3

Select * from articles where id in 
(select max(arhastypes.article_id) from arhastypes where type_id=1)

Answer 4

以下查询应该会为您提供添加到每种类型的最后一篇文章（假设id列为AUTO INCREMENT）：

select arhastypes.type_id, articles.title, articles.description from articles join arhastypes on arhastypes.article_id = articles.id order by articles.id desc group by arhastypes.type_id

Answer 5

尝试：

select top 1 from articles
order by ID desc

select top 1 from arhastypes
order by ID desc

Answer 6

尝试这样的事情：

Select  A.*
From    Articles    A
Where   A.id In
(
    Select  Max(article_id)
    From    arhastypes
    Where   type_id = @type_id
)

要为每种类型添加最新文章到每种类型，您可以执行以下操作：

Select  T.type_id, A.*
From    Articles    A
Join    arhastypes  T On A.id = T.article_id
Where   A.id In
(
    Select  Max(article_id)
    From    arhastypes
    Group By type_id
)

Answer 7

每次都有效：

Select  A.*
From    Articles    A
ORDER BY A.id DESC
LIMIT 1

用于检索最后一条记录的SQL查询

7 个答案: