字符串消息以bullet-in开头需要在nextLine中

Question

我有字符串消息，其中包含如下信息。

这里我试图在行以数字后跟。（句号）

时溢出消息

String str="1. Hi this is test 2. this is also test 3. this is also test 4. this
is also test 5. this is also test";

想要输出

1.Hi this is test
2. this is also test
3. this is also test
4. this is also test
5. this is also test

尝试了很多方法。但没有运气

Answer 1

您可以使用：

String str="1. Hi this is test 2. this is also test 3. this is also test 4. this
is also test 5. this is also test";

Pattern regex = Pattern.compile("[\\d]+\\.[a-z ]+", Pattern.CASE_INSENSITIVE | Pattern.UNICODE_CASE);
Matcher regexMatcher = regex.matcher(str);

Answer 2

使用regex

String str="1. Hi this is test 2. this is also test 3. this is also test 4. this is also test 5. this is also test";

for(String s : str.split("(?=\\d.)")) {
        System.out.println(s);
}