Question

道歉，如果这个问题已经得到解答，我已经做了大量的搜索，但没有得到答案。是否可以通过自己定义的字母排序。

包含单元格name的示例项：

按name ASC排序：

Brand1 Model1 Premium
Brand1 Model1 Standard
Brand1 Model1 Normal
Brand1 Model2 Normal
Brand1 Model2 Premium
Brand1 Model2 Standard
Brand1 Model3 Normal
Brand1 Model3 Premium
Brand1 Model3 Standard

但我想要定义自己的订单示例：

Brand1 Model2 Premium <- model2 firt and best version
Brand1 Model2 Normal <- model2 next alphabetical order
Brand1 Model2 Standard <- model2 next alphabetical order
Brand1 Model1 Premium <- model2 next alphabetical by premium first
Brand1 Model1 Normal
Brand1 Model1 Standard
Brand1 Model3 Premium
Brand1 Model3 Normal
Brand1 Model3 Standard

我尝试使用如下：

Case `name`
    when "Brand1 Model2 Premium" then 1
    when "Brand1 Model2 %" then 2
    when "Brand1 Model1 Premium" then 3
    when "Brand1 Model1 %" then 4
    when "Brand1 Model% Premium" then 5 <- next normal sorting only by 
    when "Brand1 Model%" then 6
    else 7
end,

当然，品牌，型号和版本是一个单元格。确切地说，它是产品的名称。我不会爆炸产品名称。

Answer 1

如果name值模式固定为brandX modelY Type，则以下解决方案应该有效。

使用ORDER BY FIELD将name拆分为所需的字词顺序。

示例：

select name from (
  select name
   , @s1:=substring( name, locate( ' ', name )+1 ) s1 -- ModelY Premium/Normal/Standard
   , @s2:=substring_index( @s1, ' ', 1 ) s2           -- ModelY
   , @s3:=substring_index( @s1, ' ', -1 ) s3          -- Premium/Normal/Standard
  from table_name
) segregated_name_results
order by 
 field( s2, 'Model2', 'Model1', 'Model3' )
 , field( s3, 'Premium', 'Normal', 'Standard' )
;

+------------------------+
| name                   |
+------------------------+
| Brand1 Model2 Premium  |
| Brand1 Model2 Normal   |
| Brand1 Model2 Standard |
| Brand1 Model1 Premium  |
| Brand1 Model1 Normal   |
| Brand1 Model1 Standard |
| Brand1 Model3 Premium  |
| Brand1 Model3 Normal   |
| Brand1 Model3 Standard |
+------------------------+

子查询的参考值：

select name
 , @s1:=substring( name, locate( ' ', name )+1 ) s1
 , @s2:=substring_index( @s1, ' ', 1 ) s2
 , @s3:=substring_index( @s1, ' ', -1 ) s3
from brand_models

+------------------------+-----------------+--------+----------+
| name                   | s1              | s2     | s3       |
+------------------------+-----------------+--------+----------+
| Brand1 Model1 Premium  | Model1 Premium  | Model1 | Premium  |
| Brand1 Model1 Standard | Model1 Standard | Model1 | Standard |
| Brand1 Model1 Normal   | Model1 Normal   | Model1 | Normal   |
| Brand1 Model2 Normal   | Model2 Normal   | Model2 | Normal   |
| Brand1 Model2 Premium  | Model2 Premium  | Model2 | Premium  |
| Brand1 Model2 Standard | Model2 Standard | Model2 | Standard |
| Brand1 Model3 Normal   | Model3 Normal   | Model3 | Normal   |
| Brand1 Model3 Premium  | Model3 Premium  | Model3 | Premium  |
| Brand1 Model3 Standard | Model3 Standard | Model3 | Standard |
+------------------------+-----------------+--------+----------+

演示 @ MySQL 5.5.32 Fiddle

Answer 2

你可以这样做：

order by substring_index(name, ' ', 2),
         (case when substring_index(name, ' ', -1) = 'Premium' then 1
               when substring_index(name, ' ', -1) = 'Standard' then 2
               when substring_index(name, ' ', -1) = 'Normal' then 3
          end)

这假设特殊字符串（“premium”等）位于name的末尾，前两个单词足以对name列进行排序。

Mysql按用户定义的高级排序

2 个答案: