Question

我正在尝试从Dialog edittext中设置Handler中的值，但是我收到错误。代码是这样的：

private Button btnstart;
private Button btnstop;
TimePicker myTimePicker;
final static int RQS_1 = 1;
TimePickerDialog timePickerDialog;
Context context;
private int n = 0;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    btnstart = (Button)findViewById(R.id.btnstart);
    btnstart.setOnClickListener(new View.OnClickListener(){
        public void onClick(View v) {
            LayoutInflater l = LayoutInflater.from(MainActivity.this);
            View dview = l.inflate(R.layout.dialog, null);
            AlertDialog.Builder ad = new AlertDialog.Builder(MainActivity.this);
            ad.setView(dview);
            final EditText edit = (EditText) dview.findViewById(R.id.edit);
            String e = edit.getText().toString();

            n = Integer.parseInt(e);

            ad.setCancelable(false)
            .setTitle("Imposta i Secondi")
            .setPositiveButton("Ok", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id){
                    Handler handler = new Handler();
                    handler.postDelayed(new Runnable(){
                        @Override
                        public void run(){
                            Toast.makeText(getApplicationContext(), "Start",Toast.LENGTH_LONG).show();
                        }
                    }, n);

                }
            })
            .setNegativeButton("Cancel",new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id){

                    dialog.cancel();
                }
            });
            AlertDialog alertD = ad.create();

            alertD.show();
        }
    });

n值，通常可以是3000,4000,5000或以ms为单位的任何其他值作为整数值。所以我在整数中转换了edittext的编辑值，但我在logcat中得到一个错误：第Invalid int ""行n = Integer.parseInt(e);这里有什么问题？

Answer 1

您需要将这两行代码从现在的位置移到DialogInterface.OnClickListener的onClick处理程序中。

String e = edit.getText().toString();
n = Integer.parseInt(e);

修订后的代码

private Button btnstart;
private Button btnstop;
TimePicker myTimePicker;
final static int RQS_1 = 1;
TimePickerDialog timePickerDialog;
Context context;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    btnstart = (Button)findViewById(R.id.btnstart);
    btnstart.setOnClickListener(new View.OnClickListener(){
        public void onClick(View v) {
            LayoutInflater l = LayoutInflater.from(MainActivity.this);
            View dview = l.inflate(R.layout.dialog, null);
            AlertDialog.Builder ad = new AlertDialog.Builder(MainActivity.this);
            ad.setView(dview);
            final EditText edit = (EditText) dview.findViewById(R.id.edit);

            ad.setCancelable(false)
            .setTitle("Imposta i Secondi")
            .setPositiveButton("Ok", new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id){

                    String e = edit.getText().toString();
                    int n = Integer.parseInt(e);

                Handler handler = new Handler();
                    handler.postDelayed(new Runnable(){
                        @Override
                        public void run(){
                            Toast.makeText(getApplicationContext(), "Start",Toast.LENGTH_LONG).show();
                        }
                    }, n);

                }
            })
            .setNegativeButton("Cancel",new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int id){

                    dialog.cancel();
                }
            });
            AlertDialog alertD = ad.create();

            alertD.show();
        }
    });

Answer 2

您的EditText在什么时候填充？这是在一个创建事件中，所以你似乎试图从空字符串中提取一个整数？

Answer 3

int value;
try{
    value = Integer.parseInt(stringValue);
}(Execption e){
    value = 0; // If edittext contains letters, space, etc
}

Answer 4

首先，您应该使用try catch来格式化数字。

String e = edit.getText().toString().trim();
   if(e!=null && !e.isEmpty())
    {
           int n ;
            try {
         n = Integer.valueOf(e);
       } catch (NumberFormatException e) {
         e.printStackTrace();
         n = 0;
       }
    }

希望它有所帮助。

从EditText转换Android整数失败

4 个答案:

修订后的代码