使用RightToLeftLayout True拖放控制

Question

我使用以下代码在C＃中拖放Button，当我的Form.RightToLeftLayout = False时，它就像魅力一样 但 当我设置RightToLeftLayout = True时 它不起作用并将控制方向移动错误!!!

  public partial class Form1 : Form
    {
        int xPosition;
        int yPosition;
        bool isDraged;
        public Form1()
        {
            InitializeComponent();
        }

        private void btnMoveable_MouseDown(object sender, MouseEventArgs e)
        {
            this.Cursor = Cursors.SizeAll;
            xPosition = e.X;
            yPosition = e.Y;
            isDraged = true;
        }

        private void btnMoveable_MouseUp(object sender, MouseEventArgs e)
        {
            isDraged = false;
            this.Cursor = Cursors.Default;

        }


        private void btnMoveable_MouseMove(object sender, MouseEventArgs e)
        {
            if (isDraged)
            {

                btnMoveable.Left = btnMoveable.Left + e.X - xPosition;
                btnMoveable.Top = btnMoveable.Top + e.Y - yPosition;

            }
        }
}

Answer 1

嗯，您正在发现RightToLeft的实施方式。一切仍处于正常的逻辑位置，但坐标系沿Y轴镜像。因此，沿X轴的运动被反转。你需要适应这一点。修正：

    int dx = e.X - xPosition;
    if (this.RightToLeft == RightToLeft.Yes) dx = -dx;
    btnMoveable.Left = btnMoveable.Left + dx;