Question

我正在制作一个调查网站，现在我正在努力回答多项选择题。一切正常，但现在我想访问用户选择的答案，但我不知道如何做到这一点。

我的初始代码看起来像那样（answersering.php）：

<?php
include_once 'init/init.funcs.php';
$_SESSION['pollid']=(int) $_GET['pollid'];
$questions = array();
if (!isset($_SESSION['answering'])) {
    $result = mysql_query('SELECT * from katse_kysimused where kysimustik_id="' . $_SESSION['pollid'] . '"');
    while($row = mysql_fetch_assoc($result)) {
        $questions[] = $row['kysimus'];
        }
    $_SESSION['answering']['questions'] = $questions;
    $_SESSION['answering']['index'] = 0;
}
    $x = $_SESSION['answering']['index'];
    $result3 = mysql_query('SELECT tyyp_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x] . '"');
    $type = mysql_result($result3, 0);
    if ($type=='3'){
        echo "<meta http-equiv='refresh' content='0;url=http://localhost/Praks/valikvastustega_kysimusele_vastamine.php'>";
        }

    if ($type=='1'){
            echo "<meta http-equiv='refresh' content='0;url=http://localhost/Praks/tekstkysimusele_vastamine2.php'>";
            $answer = $_POST['answer'];
        }

if(isset($_POST['submit'])){
    $result2 = mysql_query('SELECT kysimus_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x -1] . '"');
    $q_id = mysql_result($result2, 0);
    mysql_query('INSERT INTO katse_vastused2 (id, vastus,kysimus_id, vastustik_id) VALUES (NULL,"' . $answer . '","' . $q_id . '","1")');
    }
$_SESSION['answering']['index']++;
?>

代码的其他部分正在跟随（它用于显示多项选择题）：

<?php
include_once 'init/init.funcs.php';
$x = $_SESSION['answering']['index'];
        echo $_SESSION['answering']['questions'][$x-1];
        $result4 = mysql_query('SELECT kysimus_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x-1] . '"');
        $question_id = mysql_result($result4, 0);
        $result5 = mysql_query('SELECT * from katse_valik_vastused where kysimus_id="' . $question_id . '"');
        if($result5 === FALSE) {
            die(mysql_error());
        }
        while($row = mysql_fetch_assoc($result5)) {
            $options[] = $row['vasuts'];
        }

?>
<html>
<br>
<form method="post" action="answering.php">
<?php 
foreach($options as $option=>$option_value) {

?>

<input type="radio" name="option" value=<?$option_value?>><?php echo $option_value?><br>


<?php }?>

<input name= "submit" type="submit" value="Vasta">
</form>

为了获得答案，我尝试了以下用户提供的答案。我将以下代码添加到我的第一个文件（answering.php）中。

$selected_radio = $_POST['option'];
$_SESSION['answering']['selected_radio'] =  $selected_radio;

然后控制它是否有效，我将以下代码添加到我的第二个文件中：

print $_SESSION['answering']['selected_radio'];

但它没有用。我应该写什么以及在哪里访问多项选择题的答案？

编辑：

现在我的两段代码看起来像这样：

<?php
include_once 'init/init.funcs.php';
$_SESSION['pollid']=(int) $_GET['pollid'];
$questions = array();
if (!isset($_SESSION['answering'])) {
    $result = mysql_query('SELECT * from katse_kysimused where kysimustik_id="' . $_SESSION['pollid'] . '"');
    while($row = mysql_fetch_assoc($result)) {
        $questions[] = $row['kysimus'];
        }
    $_SESSION['answering']['questions'] = $questions;
    $_SESSION['answering']['index'] = 0;
}
    $x = $_SESSION['answering']['index'];
    $result3 = mysql_query('SELECT tyyp_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x] . '"');
    $type = mysql_result($result3, 0);
    if ($type=='3'){
        echo "<meta http-equiv='refresh' content='0;url=http://localhost/Praks/valikvastustega_kysimusele_vastamine.php'>";
        }

    if ($type=='1'){
            echo "<meta http-equiv='refresh' content='0;url=http://localhost/Praks/tekstkysimusele_vastamine2.php'>";
            $answer = $_POST['answer'];
        }

if(isset($_POST['submit'])){
    $result2 = mysql_query('SELECT kysimus_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x -1] . '"');
    $q_id = mysql_result($result2, 0);
    mysql_query('INSERT INTO katse_vastused2 (id, vastus,kysimus_id, vastustik_id) VALUES (NULL,"' . $answer . '","' . $q_id . '","1")');
    $selected_radio = $_POST['option'];
    $_SESSION['answering']['option']=$selected_radio;
}
$_SESSION['answering']['index']++;
?>

和

<?php
include_once 'init/init.funcs.php';
$x = $_SESSION['answering']['index'];
        echo $_SESSION['answering']['questions'][$x-1];
        $result4 = mysql_query('SELECT kysimus_id FROM katse_kysimused where kysimus= "' . $_SESSION['answering']['questions'][$x-1] . '"');
        $question_id = mysql_result($result4, 0);
        $result5 = mysql_query('SELECT * from katse_valik_vastused where kysimus_id="' . $question_id . '"');
        if($result5 === FALSE) {
            die(mysql_error());
        }
        while($row = mysql_fetch_assoc($result5)) {
            $options[] = $row['vasuts'];
        }

?>
<html>
<?php
echo $_SESSION['answering']['option'];
?>
<br>
<form method="post" action="answering.php">
<?php 
foreach($options as $option) {

?>

<input type="radio" name="option" value=<?php $option ?>><?php echo $option?><br>


<?php }?>

<input name= "submit" type="submit" value="Vasta">
</form>

一切似乎都很好，没有错误出现。但仍然遵循以下代码行不会打印出前一个问题的给定答案，它位于html部分开头的第二个文件中：

echo $_SESSION['answering']['option'];

但是当我改变以下部分时：

<input type="radio" name="option" value=<?php $option ?>><?php echo $option?><br>

来，让我们说：

如果我回答上一个问题，它会在问题开头打印出狗

问题似乎是我的单选按钮没有收到选项的价值，如何解决？

Answer 1

简单添加更多无线电输入。

<input type="radio" name="option" value="value1"><br>
<input type="radio" name="option" value="value2"><br>
<input type="radio" name="option" value="value3"><!-- the value defines the choice. -->

如果您点击一个按钮它会像这样收到已检查的标签。

<input type="radio" name="option" value="value1" checked><br>//this one is clicked now
<input type="radio" name="option" value="value2"><br>
<input type="radio" name="option" value="value3">

然后在你的php中执行以下操作。 $ _POST保存具有checked标签的无线电输入的值。

if(isset($_POST["option"])){ //checks if any of the buttons is checked.
    $var = $_POST["option"]; //this is now either value1, value2 
                             //or value3 depending on which was selected.
}else{                       //If there was no button selected.
    echo "must select an option";
}

//$_POST['option'] <-- 'option' here is the name of the radio button.
//$var = $_POST['option'] <-- $var will now hold the value of the checked radio button.

编辑示例

$questions = array() //instert questions can be done automaticaly probably.
//for if the question names are not unique.
$i=0;
//for all the questions
foreach($questions as $x){
    //Get all answers for the question put them in another array.
    $answers = array();
    $answers = $x->getanswers();
    //if quesionnames are not unique an increment to make question names unique.
    $x = $x.$i;
    $i++;
    //for all the answers of the found question
    foreach($answers as $y){
        //echo a radion buttion with the name of the question and the value of the answer.
        echo "<input type='radio' name='$x' value='$y'>";
    }
}

如何获得多项选择调查的答案？

1 个答案: