Question

我正在试图在java中实现serializable，但我得到了一个例外。

这是我的可序列化类：

public class Serialize implements java.io.Serializable {
        private static final long serialVersionUID = 1L;
        public double dis1;
        public double dis2;
        public double error1;
        public double error2;
        public double coorx;
        public double coory;
        public double coorz;

    }

当我创建这个类的对象并尝试转换为字节时。

Serialize serial = new Serialize();
        serial.dis1 = dis1;
        serial.dis2 = dis2;
        serial.error1 = error1;
        serial.error2 = error2;
        serial.coorx = coorx;
        serial.coory = coory;
        serial.coorz = coorz;

        byte[] bytes = null;
        int length = 0;

        try {

            ByteArrayOutputStream bs = new ByteArrayOutputStream();
            ObjectOutputStream os = new ObjectOutputStream(bs);
            os.writeObject(serial); ///EXCEPCION
            os.close();
            bytes = bs.toByteArray();
            length = bytes.length;

        } catch (IOException e) {

            e.printStackTrace();
        }

我做错了什么？

logcat的：

04-24 09:15:29.734: W/System.err(4279): java.io.NotSerializableException: org.gradiant.sistole.locservice.Communication
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1364)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeFieldValues(ObjectOutputStream.java:979)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.defaultWriteObject(ObjectOutputStream.java:368)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeHierarchy(ObjectOutputStream.java:1074)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeNewObject(ObjectOutputStream.java:1404)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObjectInternal(ObjectOutputStream.java:1671)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1517)
04-24 09:15:29.734: W/System.err(4279):     at java.io.ObjectOutputStream.writeObject(ObjectOutputStream.java:1481)
04-24 09:15:29.734: W/System.err(4279):     at org.gradiant.sistole.locservice.Communication.datarequest(Communication.java:447)
04-24 09:15:29.734: W/System.err(4279):     at org.gradiant.sistole.locservice.UWBmain.process(UWBmain.java:311)
04-24 09:15:29.734: W/System.err(4279):     at org.gradiant.sistole.locservice.UWBmain$2.run(UWBmain.java:279)
04-24 09:15:29.734: W/System.err(4279):     at java.lang.Thread.run(Thread.java:841)

感谢

Answer 1

看起来你试图序列化类org.gradiant.sistole.locservice.Communication的对象，这是你尝试序列化的类中的一个对象吗？如果是这样，那个对象也应该实现serializable来序列化对象。如果你不需要这个对象，你可以像以下那样使它成为瞬态：

 transient Communication comm = new Communication(...);

此对象不会被序列化，如果您反序列化该对象，它将为null。

如果你无法实现serializable，并且在反序列化时确实需要它，那么你必须找到一种在反序列化时重建对象的方法。

可序列化java的问题

1 个答案: