我测试了我的类成员函数,以添加到我的开关之外的链接列表并且它可以工作。但是当我尝试在我的开关中使用它时,它并没有。它实际上不会添加到列表中,因为当我显示列表时没有任何内容。
课程和实施:
#ifndef HEADER_H
#define HEADER_H
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
template <class T>
class LinkedList{
template<typename T>
class Node
{
public:
Node(T value = 0) : data(value), nextptr(NULL){};
T retrieve() const{ return data; }
Node<T> *next() const{ return nextptr; }
private:
T data;
Node<T> *nextptr;
friend LinkedList<T>;
};
public:
LinkedList();
LinkedList(const T& x); //Copy Constructor
~LinkedList();
void DisplayList();
void ReverseList();
LinkedList<T> operator= (const LinkedList<T> & x); //Assignment Operator
bool isEmpty() const{ return Size() == 0; }
int Size() const{ return n; }
bool ElementAt(int k, T& x) const;
LinkedList<T>& RemoveAt(int k, T& x)
{
if (k < 0 || k >= Size())
{
cout << "Index not in list.";
}
Node<T> *del = NULL;
if (k == 0)
{
del = list_head;
list_head = del->nextptr;
}
else
{
Node<T> *prev = list_head;
del = list_head->nextptr;
for (int i = 1; i< k; i++)
{
prev = del;
del = del->nextptr;
}
prev->nextptr = del->nextptr;
}
n--; x = del->data; delete del;
return *this;
}
LinkedList<T>& Add(const T& x)
{
Node<T>
*node = new Node<T>(x);
if (Size() == 0)
list_head = node;
else
{
Node<T> *temp = list_head;
while (temp->nextptr)
{
temp = temp->nextptr;
}
temp->nextptr = node;
}
n++;
return *this;
}
private:
Node<T> *list_head;
int n;
};
//Constructor
template<class T>
LinkedList<T>::LinkedList()
{
list_head = NULL;
n = 0;
}
//Copy Constructor
template<class T>
LinkedList<T>::LinkedList(const T& x)
{
list_head = x.listhead;
n = x.n;
}
//Destructor
template<class T>
LinkedList<T>::~LinkedList()
{
Node<T> *temp = list_head, *del, *nextptr;
while (temp != NULL)
{
del = temp->nextptr;
delete temp;
temp = del;
}
}
template<class T>
bool LinkedList<T>::ElementAt(int k, T& x) const
{
if (k < 0 || k >= Size())
return false;
Node<T> *temp = list_head;
for (int i = 0; i< k; i++)
{
temp = temp->next;
}
x = temp->data;
return true;
}
// Assignment Operator
template<class T>
LinkedList<T> LinkedList<T>::operator=(const LinkedList<T> & x)
{
list_head = x.list_head;
n = x.n;
return *this;
}
template<class T>
void LinkedList<T>::DisplayList()
{
Node<T> *temp = list_head;
while (temp != NULL)
{
cout << temp->data << endl;
temp = temp->nextptr;
}
}
template<class T>
void LinkedList<T>::ReverseList()
{
Node<T> *t, *y = list_head, *r = NULL, *listhead;
while (y != NULL)
{
t = y->nextptr;
y->nextptr = r;
r = y;
y = t;
}
list_head = r;
}
#endif
司机:
#include "stdafx.h"
#include <iostream>
#include "Header.h"
using namespace std;
int main()
{
int choice;
string item;
do
{
LinkedList<string> list;
int num;
cout << "1. Add new record to the file" << endl;
cout << "2. Delete a record in the file (by index)" << endl;
cout << "3. Display entire list of items" << endl;
cout << "4. Display entire list of items backwards" << endl;
cout << "5. Exit" << endl;
cin >> choice;
switch (choice)
{
case 1:
{
cout << "1. Add new record to the file" << endl;
cout << "Enter the Item Description:" << endl;
cin.ignore();
getline(cin, item);
list.Add(item);
}
break;
case 2:
{
cout << "2. Delete a record in the file" << endl;
cout << "Enter the index number of the item you want to delete" << endl;
cin >> num;
//list.RemoveAt(num);
}
break;
case 3:
{
cout << "3. Display entire list of items" << endl;
list.DisplayList();
}
break;
case 4:
{
cout << "4. Display entire list of items backwards" << endl;
list.ReverseList();
list.DisplayList();
list.ReverseList();
}
break;
case 5:
{
return 0;
}
break;
}
} while (0 < choice < 6);
return 0;
}
有什么想法吗?
答案 0 :(得分:1)
将list
声明移到do..while
循环之外。目前,每次循环都会重新初始化。