Question

我在附加代码的一行中遇到引号问题。

它是图片浏览器的一部分。图片数据网址“PicNotes”从mysql中读取。我试图通过添加图片信息弹出窗口来增强结果，但无法正确获取引号。

我在3个版本（尝试）中添加了一些rem语句以使其正常工作。

    $data = mysql_query("SELECT * FROM $tbl_name WHERE type='$type' LIMIT $start, $limit_col_1");}
// Your while loop here
while($row = mysql_fetch_array($data))
{//REM If there is no info don't show the info link
    if ($row[PicNotes]) {
//  $icon=<a href="JavaScript:Popup('notes/$row['PicNotes']');"> <img src='images/info.png'></a>; //REM This line was the original call for the pop-up script
//  $icon = "<a href=notes/tempest_series.php><img src=images/info.png></a>"; //REM This line works but does not have any of the Jarvascript or URL variable from the DB
//  $icon = "<a href=notes/$row[PicNotes]><img src=images/info.png></a>"; //REM This  line doesn't crash but the URL is corrupted
    $icon = "<a href="JavaScript:Popup(notes/$row[PicNotes]);"><img src=images/info.png></a>"; //REM This line crashes with an "Unexpected T_STRING error 
    }else{
    $icon='';}
// Display LHS Thumbnail and Viewer Pic Data

    echo "<a href='images/".$row['vfile']."' rel='enlargeimage::mouseover' rev='loadarea' title='&lt;b&gt;".$row['Title']."&lt;/b&gt;&lt;br /&gt;".$row['Medium']." &nbsp; &nbsp; &nbsp; ".$row['iw']." x ".$row['ih']." cm. $icon'><img border='1' src='images/".$row['tnfile']."
    ' alt='' width='".$row['tnx']."' height='".$row['tny']."' class='tn' /></a><br />";

}

请有人能让我走上正轨。

Answer 1

1）逃避内部引号：

$icon = "<a href=\"JavaScript:Popup(notes/$row[PicNotes])\"><img src=images/info.png></a>";

2）使用单引号：

$icon = "<a href='JavaScript:Popup(notes/$row[PicNotes])'><img src=images/info.png></a>";

Answer 2

使用花括号（{}）来获得更好的变量连接

$icon="<a href=\"JavaScript:Popup('notes/{$row[PicNotes]}');\"><img src=\"images/info.png\"></a>";

php Javascript变量引用错误

2 个答案: