总计/平均/更改工资1,2,3,4菜单

时间:2014-04-23 13:30:47

标签: python python-3.3

更改您的程序,以便管理员有一个主菜单可供选择,有四个选项:

  1. 打印每周工资总额。
  2. 打印平均工资。
  3. 更改玩家的工资。
  4. 退出
  5. 当我运行程序时,我输入数字1,程序停止。如何将其链接到以下4个程序?

    程序:

    Chelsea_Salaries_2014 = {'Jose Mourinho':[53, 163500, 'Unknown']}
    Chelsea_Salaries_2014['Eden Hazard']=[22, 185000, 'June 2017']
    Chelsea_Salaries_2014['Fernando Torres']=[29, 175000, 'June 2016']
    Chelsea_Salaries_2014['John Terry']=[32, 175000, 'June 2015']
    Chelsea_Salaries_2014['Frank Lampard']=[35, 125000, 'June 2014']
    Chelsea_Salaries_2014['Ashley Cole']=[32, 120000, 'June 2014']
    Chelsea_Salaries_2014['Petr Cech']=[31, 100000, 'June 2016']
    Chelsea_Salaries_2014['Gary Cahill']=[27, 80000, 'June 2017']
    Chelsea_Salaries_2014['David Luiz']=[26, 75000, 'June 2017']
    Chelsea_Salaries_2014['John Obi Mikel']=[26, 75000, 'June 2017']
    Chelsea_Salaries_2014['Nemanja Matic']=[25, 75000, 'June 2019']
    Chelsea_Salaries_2014['Marco Van Ginkel']=[20, 30000, 'June 2018']
    Chelsea_Salaries_2014['Ramires']=[26, 60000, 'June 2017']
    Chelsea_Salaries_2014['Oscar']=[21, 67500, 'June 2017']
    Chelsea_Salaries_2014['Lucas Piazon']=[19, 15000, 'June 2017']
    Chelsea_Salaries_2014['Ryan Bertrand']=[23, 35000, 'June 2017']
    Chelsea_Salaries_2014['Marko Marin']=[27, 35000, 'June 2017']
    Chelsea_Salaries_2014['Cesar Azpilicueta']=[23, 55000, 'June 2017']
    Chelsea_Salaries_2014['Branislav Ivanovic']=[29, 67500, 'June 2016']
    Chelsea_Salaries_2014['Ross Turnbull']=[22, 17000, 'June 2017']
    Chelsea_Salaries_2014['Demba Ba']=[28, 65000, 'June 2016']
    Chelsea_Salaries_2014['Oriol Romeu']=[22, 15000, 'June 2015']
    
    user_input = (int('Welcome! What would you like to do? 1: Print the total salaries bill. 2: Print the average salary. 3: Change a players salary. 4: Quit. '))
    
    if user_input == 1:
        print(sum(i[1] for i in Chelsea_Salaries_2014.values()))
    else:
        if user_input == 2:
           print(sum(i[1] for i in Chelsea_Salaries_2014.values()))/len(Chelsea_Salaries_2014)
        else:
            if user_input == 3:
                def change_salary(Chelsea_Salaries_2014):
                    search_input = input('What player would you like to search for? ')
                    print('His Current Salary is £{0:,}'.format(Chelsea_Salaries_2014[search_input][1]))
                    new_salary = int(input('What would you like to change his salary to? '))
                if new_salary <= 200000:
                    Chelsea_Salaries_2014[search_input][1] = new_salary
                    print('Salary has been changed to £{0:,}'.format(new_salary))
                else:
                    print('This salary is ridiculous!')
    
                while True:
                    change_salary(Chelsea_Salaries_2014)
                    choice = input("Go again? y/n ")
                    if choice.lower() in ('n', 'no'):
                            break
            else:
                if user_input == 4:
                    print('Goodbye!')
    

1 个答案:

答案 0 :(得分:0)

暂停原始输入。

 while True:
 user_input = raw_input("Welcome!...")
 if user_input == 1:
  ...
 elif user_unput == 2:
  ...
 else:
  print "this salary is ridic..."

完成1,2,3 ...输入后询问用户是否愿意做其他事情,如果n:break,这将结束循环。如果为y,则循环再次开始,并要求另一个用户输入。