Question

这是我书店的简单代码代码没有任何问题。我正在使用DevC ++来运行代码，并且在编译之后它会发出一个错误，其中“获取”未在此范围内声明＆amp; put的错误相同。请帮我。

#include<iostream>
#include<conio.h>
#include<stdlib.h>
#include<iomanip>
#include<cstring>

using namespace std;

class Book
{
    char *title,*author,*publisher,ans;
    int price,quant,quant_ent;

    public:
            Book()
            {
        title = new char[50];
        author = new char[50];
        publisher = new char[50];
        price = quant = quant_ent = 0;
            }

        void getdata()
        {
            cout<<"\nEnter The Title";
            gets(title);
            cout<<"\nEnter The Author";
            gets(author);
            cout<<"\nEnter The Publisher";
            gets(publisher);
            cout<<"\nEnter The Price";
            cin>>price;
            cout<<"\nEnter The Quantity";
            cin>>quant;
        }

    void display()
    {
        cout<<setw(15)<<title<<setw(15)<<author<<setw(15)<<publisher<<setw(10)<<quant
            <<setw(10)<<price;
    }

    void search(char search_title[],char search_author[])
    {
        if(strcmpi(author,search_author)==0)
        {
            if(strcmpi(title,search_title)==0)
            {
                cout<<"\nBook Found!";
                cout<<"\nEnter The Quantity: ";
                cin>>quant_ent;
                if(quant_ent <= quant)
                {
                    cout<<"\nThe Title is: ";
                    puts(title);
                    cout<<"\nThe Author is: ";
                    puts(author);
                    cout<<"\nThe Publisher is: ";
                    puts(publisher);
                    cout<<"\nPrice Of Single Copy: "<<price;
                    cout<<"\nTotal Price = "<<price*quant_ent;
                    quant = quant - quant_ent;
                }

                else
                {
                    cout<<"\nSufficient Quantity Not Available!";
                }
            }
        }
    }
};


int main()
{
Book obj[10];
int i=0,ch;

char author[50],title[50];

for(;;)
{
    cout<<"\n*******MENU********\n1)Enter Details\n2)Buy Book\n3)Display All Books\n4)Exit";
    cin>>ch;

    switch(ch)
    {
        case 1:
            obj[i].getdata();
            i++;
            break;

        case 2:
            cout<<"\nEnter The Authors Name: ";
            gets(author);
            cout<<"\nEnter The Title: ";
            gets(title);
            for(int j=0;j<i;j++)
            {
                obj[j].search(title,author);
            }

            break;

        case 3:
            cout<<setw(15)<<"TITLE"<<setw(15)<<"AUTHOR"<<setw(15)<<"PUBLISHER"<<setw(15)<<"QUANTITY"<<setw(15)<<"PRICE";
            cout<<"\n"<<setw(75)<<"-----------------------------------------------------------------------------------------------------";
            for(int j=0;j<i;j++)
            {
                cout<<"\n";
                obj[j].display();
            }

        case 4:
            exit(1);
    };
}
}

Answer 1

因为它在stdio.h（C ++中的cstdio）标头中声明，并且您没有包含它。

但是you shall not use gets.这是一个无可救药的破坏功能。请改用fgets。更好的是，将裸指针抛弃到char数组并改为使用std::string类。

得到（）＆amp; puts（）未在dev c ++的范围内声明

1 个答案: