阅读jquery gzipped json数据

Question

需要通过php函数打包gzencode来处理数据。 Gzencode很重要，因为数据量超过30MB！

PHP

header('Pragma: no-cache');
header('Cache-Control: private, no-cache');
header('Content-Disposition: inline; filename="files.json"');
header('Content-type: application/json; charset=utf-8');
header('Content-Encoding: gzip');
header('Vary: Accept-Encoding');

echo gzencode ( json_encode ( $arr ) );

的Javascript

jQuery.ajax({
    url: path,
    type: 'POST',
    data: data,
    headers: {"Content-Encoding": "gzip"},
    dataType: 'json',
    success: [jQuery.ajaxCallback, function()
    {
        // manipulation with json object data
    }]
});