由于某些原因,在使y.hat成为一个单独的函数后,我的代码不再起作用了。有什么想法吗? 这是我收到的错误:
> source("y.hat.R")
Time-Series [1:60] from 1912 to 1971: 49.9 52.3 49.4 51.1 49.4 47.9 49.8 50.9 49.3 51.9 ...
Error in as.double(y) :
cannot coerce type 'closure' to vector of type 'double'
这是我的代码: 要求(数据集) 数据(nhtemp) STR(nhtemp)
y.hat<-function(beta,y=nhtemp){
y.hat=numeric(length(y))
y.hat[1]=y[1]
y.hat[2]=y[2]
for (i in 3:length(y))
{
y.hat[i]=beta*y[i-1]+(1-beta)*y.hat[i-1]
}
return(y.hat)
}
mona.function <- function(beta, y=nhtemp){
n<-length(y)
y.hat<-y.hat(beta,nhtemp)
sq.sum=0
for (i in 2:n)
{
sq.sum = sq.sum + (y[i]-y.hat[i])^2
}
return(sq.sum/n)
}
opt.result=optimize(mona.function, c(0,1), maximum=FALSE)
y.hat(opt.result$minimum,nhtemp)
plot(nhtemp)
lines(ts(y.hat, start = start(nhtemp)[1], end = end(nhtemp)[1]), col = "red")
beta=0.1
y.hat<-y.hat(beta,nhtemp)
lines(ts(y.hat, start = start(nhtemp)[1], end = end(nhtemp)[1]), col = "green")
beta=0.9
y.hat<-y.hat(beta,nhtemp)
lines(ts(y.hat, start = start(nhtemp)[1], end = end(nhtemp)[1]), col = "blue")
答案 0 :(得分:1)
您使用语句
覆盖了函数y.hat
的定义
y.hat<-y.hat(beta,nhtemp)
我想你想做点什么
y.hat.value <- y.hat(beta,nhtemp)