Question

我正试图在counts number of rows中table 12 months逐月12 counts获得SELECT ( SELECT COUNT(i.id) FROM intrusions i, devices d WHERE i.device_id = d.id AND d.primary_owner_id = '1' AND FROM_UNIXTIME(start_time/1000) like '2014-04%', SELECT COUNT(i.id) FROM intrusions i, devices d WHERE i.device_id = d.id AND d.primary_owner_id = '1' AND FROM_UNIXTIME(start_time/1000) like '2014-03%', SELECT COUNT(i.id) FROM intrusions i, devices d WHERE i.device_id = d.id AND d.primary_owner_id = '1' AND FROM_UNIXTIME(start_time/1000) like '2014-02%', etc )，1 user

到目前为止，我有这种非常丑陋的方式：

many devices

这些表已设置好，1 device可以many intrusions而primary_owner_id可以有date，因此需要额外的条件。

将使用PHP在prepared statements中动态添加{{1}}和{{1}}。有没有更好的方法来写出来，这不会涉及如此多的重复和绑定24个参数？任何帮助将不胜感激

Answer 1

您应该使用分组来实现此目的。就像这样。

SELECT
    CONCAT(YEAR(FROM_UNIXTIME(start_time/1000)), '-', MONTH(FROM_UNIXTIME(start_time/1000))) AS `year_month`,
    COUNT(id) AS `count`
FROM intrusions AS i
INNER JOIN devices AS d
  ON i.device_id = d.id
WHERE d.primary_owner = ?
GROUP BY `year_month`
ORDER BY `year_month` DESC
LIMIT 12

Answer 2

您可以使用DATE_FORMAT选择年份和月份，并且可以使用DATE_SUB创建WHERE条件，选择上个月的项目。 Haven没有测试过这种语法，但它应该接近正确。

这与最后一个答案一致，但首先使用更简洁的DATE_FORMAT并使用DATE_SUB自动选择过去12个月来改进

SELECT
  DATE_FORMAT(start_date, "%Y-%m") AS `month`,
  COUNT(`id`) AS `count`
FROM intrusions
INNER JOIN devices ON (intrusions.device_id = devices.id)
WHERE
  d.primary_owner_id = 1 AND
  DATE_SUB(CUR_DATE(), INTERVAL 12 MONTH) < start_date
GROUP BY month
ORDER BY month DESC

MySQL查询按月返回行数

2 个答案: