我在 Matlab 中编写了一个项目，但是我想要执行的效率和速度，为此，我想要在 Matlab 中使用并行处理 线程，因为我有多个对象正在工作或更改其状态< / em>在 for循环中。 多线程是否适用于此目的？如果是这样，我可以在哪里开始或者可以创建一个简单的线程？
我的代码：
% P=501x3 array
for i=1:length(P)
% I used position for example's sake, meaning object changing its state
Object1.position=P(i,:);
Object2.position=P(i,:);
Object3.position=P(i,:);
Object4.position=P(i,:);
% Mulitple objects changing their state on each iteration, after some calculation/formulation.
end
根据我的场景，我需要的是多线程的基本结构，如果线程在我的情况下是合适的。欢迎提供有关并行执行或快速处理的更多建议。
Edit1：P数组：
P =
-21.8318 19.2251 -16.0000
-21.7386 19.1620 -15.9640
-21.6455 19.0988 -15.9279
-21.5527 19.0357 -15.8918
-21.4600 18.9727 -15.8556
-21.3675 18.9096 -15.8194
-21.2752 18.8466 -15.7831
-21.1831 18.7836 -15.7468
-21.0911 18.7206 -15.7105
-20.9993 18.6577 -15.6741
-20.9078 18.5947 -15.6377
-20.8163 18.5318 -15.6012
-20.7251 18.4689 -15.5647
-20.6340 18.4061 -15.5281
-20.5432 18.3432 -15.4915
-20.4524 18.2804 -15.4548
-20.3619 18.2176 -15.4181
-20.2715 18.1548 -15.3814
-20.1813 18.0921 -15.3446
-20.0913 18.0293 -15.3078
-20.0015 17.9666 -15.2709
-19.9118 17.9039 -15.2340
-19.8223 17.8412 -15.1970
-19.7329 17.7786 -15.1601
-19.6438 17.7160 -15.1230
-19.5547 17.6534 -15.0860
-19.4659 17.5908 -15.0489
-19.3772 17.5282 -15.0117
-19.2887 17.4656 -14.9745
-19.2004 17.4031 -14.9373
-19.1122 17.3406 -14.9001
-19.0241 17.2781 -14.8628
-18.9363 17.2156 -14.8254
-18.8486 17.1532 -14.7881
-18.7610 17.0907 -14.7507
-18.6736 17.0283 -14.7132
-18.5864 16.9659 -14.6758
-18.4994 16.9035 -14.6383
-18.4124 16.8412 -14.6007
-18.3257 16.7788 -14.5632
-18.2391 16.7165 -14.5255
-18.1526 16.6542 -14.4879
-18.0663 16.5919 -14.4502
-17.9802 16.5296 -14.4125
-17.8942 16.4673 -14.3748
-17.8084 16.4051 -14.3370
-17.7227 16.3429 -14.2992
-17.6372 16.2807 -14.2614
-17.5518 16.2185 -14.2235
-17.4665 16.1563 -14.1856
-17.3815 16.0941 -14.1477
-17.2965 16.0320 -14.1097
-17.2117 15.9698 -14.0718
-17.1271 15.9077 -14.0338
-17.0426 15.8456 -13.9957
-16.9582 15.7835 -13.9576
-16.8740 15.7214 -13.9196
-16.7899 15.6594 -13.8814
-16.7060 15.5973 -13.8433
-16.6222 15.5353 -13.8051
-16.5385 15.4733 -13.7669
-16.4550 15.4113 -13.7287
-16.3716 15.3493 -13.6904
-16.2884 15.2873 -13.6521
-16.2053 15.2253 -13.6138
-16.1223 15.1634 -13.5755
-16.0395 15.1014 -13.5372
-15.9568 15.0395 -13.4988
-15.8742 14.9776 -13.4604
-15.7918 14.9157 -13.4220
-15.7095 14.8538 -13.3835
-15.6273 14.7919 -13.3451
-15.5453 14.7301 -13.3066
-15.4634 14.6682 -13.2681
-15.3816 14.6063 -13.2295
-15.2999 14.5445 -13.1910
-15.2184 14.4827 -13.1524
-15.1370 14.4209 -13.1138
-15.0557 14.3591 -13.0752
-14.9746 14.2973 -13.0366
-14.8936 14.2355 -12.9979
-14.8127 14.1737 -12.9593
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-14.6513 14.0502 -12.8819
-14.5707 13.9885 -12.8432
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-12.3621 12.2628 -11.7535
-12.2848 12.2012 -11.7144
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-8.0882 8.7554 -9.5279
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-7.7967 8.5089 -9.3727
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-7.5060 8.2623 -9.2177
-7.4335 8.2006 -9.1790
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-7.2885 8.0772 -9.1017
-7.2161 8.0155 -9.0630
-7.1438 7.9538 -9.0244
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-6.9992 7.8304 -8.9472
-6.9270 7.7687 -8.9086
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16.9164 -12.4974 0.1853
17.0117 -12.5706 0.2001
17.1072 -12.6439 0.2148
17.2029 -12.7172 0.2293
17.2988 -12.7906 0.2437
17.3949 -12.8640 0.2580
17.4911 -12.9376 0.2721
17.5876 -13.0111 0.2861
17.6843 -13.0848 0.3000
答案 0 :(得分：0)
阿赫桑，
我认为parfor可能是您正在寻找的。它需要并行计算工具箱（PCT）才能使用。它的工作原理如下：
parfor i = 1:length(P)
Object1.position = P(i,:);
end
此外，我建议使用索引结构字段，正如我在下面的示例中所做的那样，因为它增加了您编写的任何代码的灵活性。如果这对您不起作用，请告诉我们，我们会尝试别的东西。我知道另一种技术，但它更麻烦。祝你好运！
parfor i = 1:length(P)
Object(i).position = P(i,:);
end
编辑：好的，这可能行不通，因为parfor非常特别。但它的一般概念应该适用于你试图解决的问题。在不了解您的具体问题的情况下，我无法更具体。关键的一点是，在parfor中，你必须通过parfors迭代器（下面的i）迭代某些东西（下面的Object）并为该东西赋值。我不确定你是否可以在parfor中使用for-loop，所以下面的第一个例子可能会破坏。关键是，这是你在MATLAB中进行并行处理的方法。试试这个：
parfor i = 1:4
Object(i).position = P(i,:);
end
编辑2：
parfor i = length(P)
Object1 = struct();
Object1.position = P(i, :);
end
编辑3：好的，最后一件事。你不能使用＆＃34;切片＆＃34;结构（带有字段的结构）作为parfor的输入或输出，所以你必须这样做：
parfor i = 1:length(P)
positionArray1(i) = P(i, :);
end
Object1 = struct('position', positionArray1);